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sergey [27]
3 years ago
13

A line passes through the point (-6,7) and has a slope of -4/3. Write an equation in slope-intercept form for this line.

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
6 0

Answer:

Step-by-step explanation:

y-7= -4/3 (x+6)

y-7= -4/3x-8

add 7 to both sides

y= -4/3x-1

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The terms, coefficients, and constants in the expression 3x+10
xz_007 [3.2K]

Answer:

Terms = x

Coefficients = 3

Constants = 10

Hope this helped! :)

4 0
4 years ago
I posted a question similar to this yesterday and I understand how to do it now, but I want to make sure that I did this questio
Mariulka [41]

Answer:

  Your choice is correct.

Step-by-step explanation:

magnitude = √(6² +5²) = √61 ≈ 7.81

direction = arctan(5/6) ≈ 39.81°

The polar coordinates are (7.81, 39.81°).

7 0
4 years ago
What is the measure of angle C?
Serggg [28]
Use the law of sines....(sina/A=sinb/B=sinc/C  for any triangle)

What that means is the sine of an angle divided by the length of the side opposite the angle is a ratio that is true each angle/side pair...In this case:

sin90/122=sinc/22  rearrange to solve for sinc

sinc=(22sin90)/122  now take the arcsin to solve for c

c=arcsin[(22sin90)/122]

c≈10.388857815469611987441020361405

c≈10.39° (to nearest hundredth of a degree)
3 0
3 years ago
1) 2a × 2b 2) 3a × 2b × 2a 3) 2a × 4b × b 4) 3b × 2a × b 5) 3a × 2b × 2c 6) 2a × 3b × b × c 7) a × 4b × 2a × 2c 8) 3a × 3b × 3c
podryga [215]

Step-by-step explanation:

1) = 4ab

2) 12a2b

3) 8ab2

4) 6ab2

5) 12abc

6) 6ab2c

7) 16a2bc

8) 27abc

6 0
4 years ago
What is the equation of the line that passes through (12,-3) and is perpendicular to y = -6x + 4?
Oksana_A [137]
The slope of the given line is -6, so your perpendicular line will have slope 1/6. The point-slope form of the equation of a line can be used.
.. y = (1/6)(x -12) -3
This can be simplified to
.. y = (1/6)x -5

5 0
3 years ago
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