Complete Question
A certain 50 cm spring will stretch (in cm) one fifth the weight (in kg) attached to it. How long will the spring be if a 35 kg weight is attached to it
Answer:
The value is
Step-by-step explanation:
The length of the spring is
The mass attached to it is
Generally given from that the spring will stretch one fifth of the weight (in kg)attached to it , it then means that the new length of the spring whenever a weight is attached to it is mathematically represented as
=>
=>
Answer:
6,138
Step-by-step explanation:
Given the following:
Vocalist needed :
First day (a) = 6
For subsequent days : number doubles
Using the relation. :
Sn = a(r^n -1)/(r -1)
Where a = first term = 6
r = common ratio = r3/r2 = r4/r3
Since number doubles after each consecutive day, then ; r = 2, n = 10
Sn = 6(2^10 -1)/(2 -1)
Sn = 6(1024 - 1) / 1
Sn = 6144 - 6
Sn = 6138
Answer:
26 I guess
Step-by-step explanation:
90 - 64 = 26
am I wrong?