Pleaseeeeee Simplify t12/16

Mathematics

1 answer:

yKpoI14uk [10]3 years ago

3 0

6/8 then 3/4 so your answer is 3/4 cause you can simply by 2

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Can I get some help pls!!!

kramer

Answer:

Step-by-step explanation:

7 0

3 years ago

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NO LINKS!!! Part 1: y = x^3 Shape: Domain: Range: Locater point:

LiRa [457]

Answer:

Shape: Not sure what to put

Domain: ( -oo, oo )

Range: ( -oo, oo )

Locater point: ( 0, 0 )

Step-by-step explanation:

Shape - You have the shape on the graph

Domain and Range - Both go on forever since there is no hole/interruption

Locater Point: I would say origin because it is the closest thing to a vertex, which is an example of a locater point.

Hopefully this helps!

Brainliest please?

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3 years ago

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Root 3 cosec140° - sec140°=4 prove that

Lorico [155]

Answer:

Step-by-step explanation:

We are to show that $\sqrt{3} cosec140^{0} - sec140^{0} = 4\\$

Proof:

From trigonometry identity;

$cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}$

$\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\$

From trigonometry, 2sinAcosA = Sin2A

$= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\= \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2 \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}$