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julsineya [31]
2 years ago
12

Enter a phrase for the expression. 49s

Mathematics
1 answer:
Rainbow [258]2 years ago
5 0
I don’t get this explain it better
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Identify the pairs of corresponding angles
topjm [15]

Answer: A

Step-by-step explanation:

If you flip the second triangle straight upwards so that x is on top and z,y are on the bottom, you could visualize the points and angles in the same locations.

6 0
2 years ago
What is x in this geometry equation?​
lesya [120]

Answer:

x = 7

Step-by-step explanation:

m\overset{\frown} {PQ} = m\overset{\frown} {MN}... (given) \\\therefore Chord \:PQ \cong Chord\: MN\\  \therefore \: 4x + 10 = 38 \\   \therefore \: 4x= 38  - 10\\ \therefore \: 4x= 28\\  \therefore \: x=  \frac{28}{4} \\   \huge \red{ \boxed{\therefore \: x= 7}}

8 0
3 years ago
A store pays $85 for a picnic table and marks the price up by 25%. What is the new price ​
Setler79 [48]
106


Mark brainliest please


Hope this helps you
7 0
2 years ago
Read 2 more answers
Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!
il63 [147K]

Answer:

x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

Step-by-step explanation:

w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

6 0
3 years ago
Josh buys cucumbers that cost $0.62 per pound.He pays $2.79 for the cucumbers.
Sphinxa [80]
Please refer to the other post you saw.

Josh's estimate IS reasonable because when you have a number 5 or above after the decimal, you round up. Although it's reasonable to round up to 5 pounds, the actual amount is 4.5 pounds, or four and a half.
5 0
3 years ago
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