Answer:
d=8km
Step-by-step explanation:
explanation is in the image above
Based on the 5 trials, 1 carton of eggs is expected to contain at least one broken egg, on average
<h3>How to determine the number of cartons</h3>
From the question, we understand that only one of the first 10 double-digit numbers is between 01 and 08
This means that:
The average carton or the expected value of eggs in the simulation is 1
Hence, 1 carton of eggs is expected to contain at least one broken egg, on average
Read more about expected values at:
brainly.com/question/15858152
Answer:
Jada should have multiplied both sides of the equation by 108.
Step-by-step explanation:
The question is incomplete. Find the complete question in the comment section.
Given the equation -4/9 = x/108, in order to determine Jada's error, we need to solve in our own way as shown:
Step 1: Multiply both sides of the equation by -9/4 as shown:
-4/9 × -9/4 = x/108 × -9/4
-36/-36 = -9x/432
1 = -9x/432
1 = -x/48
Cross multiplying
48 = -x
x = -48
It can also be solved like this:
Given -4/9 = x/108
Multiply both sides by 108 to have:
-4/9 * 108 = x/108 * 108
-4/9 * 108 = 108x/108
-432/9 = x
x = -48
Jada should have simply follow the second calculation by multiplying both sides of the equation by 108 as shown.
Answer:
450 minutes
Step-by-step explanation:
15 + 0.1x = 60
15 - 15 + 0.1x = 60 - 15
0.1x = 45

x = 450
Answer: Lucy ate more pizzas because he ate more inches of pizza than Anthony.
Step-by-step explanation:
Anthony eats 2 slices of a large 18 inch pizza. Total number of slice in the 18 inch pizza is 8
The size of one slice in inches would be total length of pizza / number of slices. It becomes
18 / 8 = 2.25 inches
Anthony ate 2 ×2.25 = 4.5 inches of pizza.
Lucy eats 4 slices of a 12 inch pizza.
Total number of slice in the 12inch pizza is 8
The size of one slice in inches would be total length of pizza / number of slices. It becomes
12 / 8 = 1.5 inches
Lucy ate 4 × 1.5 = 6 inches of pizza.
Lucy ate more pizzas because he ate more inches of pizza than Anthony.