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2 years ago

3rs - 5cr - 15cs + 25c2

Mathematics

2 answers:

Montano1993 [528]2 years ago

4 0

$3rs-5cr-15cs+25c^2=r(3s-5c)-5c(3s-5c)\\\\=(3s-5c)(r-5c)\\\\Answer:\ \boxed{3rs-5cr-15cs+25c^2=(3s-5c)(r-5c)}$

grigory [225]2 years ago

3 0

Your answer would be 3rs-5cr-15cs+50c

A trick that I have learned, but does not apply to all equations, (some don’t work with this) is to multiply +25c by 2 to get =50c.

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Easy problems I'm having trouble remembering how to do!

beks73 [17]

<h2>Answer:</h2>

1. - 2°C + 4°C

= 2°C.

2. 3/4 × 4

= 3pounds.

7 0

2 years ago

A circle has the center of (1,-5) and a radius of 5 determine the location of the point (4,-1)

Sliva [168]

"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.

well, we can check by simply getting the distance from the center to the point (4,-1).

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}$

5 0

2 years ago

5z3 - 224 - 9z2 + 2 What is the degree of the polynomial? I

hoa [83]

Answer:

5{z}^{3}-222-9{z}^{2}5z

−222−9z

Step-by-step explanation:

1 Collect like terms.

5{z}^{3}+(-224+2)-9{z}^{2}5z

+(−224+2)−9z

2 Simplify.

5{z}^{3}-222-9{z}^{2}5z

−222−9z

Done

7 0

2 years ago

-4.8f+6.4=-8.48 what's f 7.3y-5.18=-51.9 what's y

stich3 [128]

F=4 and y=3 those are the answers

8 0

2 years ago

The weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation

Korvikt [17]

Answer:

The z-score of a male bird of this species with a weight of 29.37 grams is 1.7.

Step-by-step explanation:

We are given that the weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation of 1.1 grams.

Let X = weights of adult male birds of a certain species

So, X ~ Normal( $\mu=27.5,\sigma^{2} =1.1^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{ X-\mu}{\sigma } }$ ~ N(0,1)

where, $\mu$ = population mean weight = 27.5 grams

$\sigma$ = standard deviation = 1.1 grams

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

SO, the z-score of a male bird of this species with a weight of 29.37 grams is given by;

Z score = $\frac{ X-\mu}{\sigma } }$ = $\frac{ 29.37-27.5}{1.1 } }$

= 1.7

4 0

2 years ago