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9966 [12]
3 years ago
5

3rs - 5cr - 15cs + 25c2

Mathematics
2 answers:
Montano1993 [528]3 years ago
4 0

3rs-5cr-15cs+25c^2=r(3s-5c)-5c(3s-5c)\\\\=(3s-5c)(r-5c)\\\\Answer:\ \boxed{3rs-5cr-15cs+25c^2=(3s-5c)(r-5c)}

grigory [225]3 years ago
3 0
Your answer would be 3rs-5cr-15cs+50c

A trick that I have learned, but does not apply to all equations, (some don’t work with this) is to multiply +25c by 2 to get =50c.
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3 years ago
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What is missing for the following quantity to be true? (3y*5b)*10 = __(5b*10)
labwork [276]
<span>(3y*5b)*10 = __(5b*10)

</span>15yb *10 = __(5b*10)
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Do you have any questions?

3y is the answer<span>.</span>
5 0
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