1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lawyer [7]
2 years ago
14

There are 12 boys and 16 girls in a classroom. Which represents the simplified ratio of girls to students in the classroom?

Mathematics
1 answer:
dedylja [7]2 years ago
4 0

We know that there are 16 girls. That is the first part of the ratio. Now, it says girls to students, which mean you have to add up the total of girls and boys together. 12+16=28. There are 28 students in total. Now, you have the ratio of 16:28. But, it says simplified...so we need to divide both sides of the ratio by a number. Let's choose 4 because 4 can go both into 16 and 28. 16/4=4. 28/4=7. So, the simplified ratio of girls to students in the classroom is 4:7.

Hope this helped!

You might be interested in
How do you find a volume of a cone?
Dennis_Churaev [7]

Answer:

  V = (1/3)πr²h

Step-by-step explanation:

The volume of a cone is 1/3 the volume of a cylinder with the same radius and height.

  Cylinder Volume = πr²h

  Cone Volume = (1/3)πr²h

where r is the radius (of the base), and h is the height perpendicular to the circular base.

_____

<em>Comment on area and volume in general</em>

You will note the presence of the factor πr² in these formulas. This is the area of the circular base of the object. That is, the volume is the product of the area of the base and the height. In general terms, ...

  V = Bh . . . . . for an object with congruent parallel "bases"

  V = (1/3)Bh . . . . . for a pointed object with base area B.

This is the case for any cylinder or prism, even if the parallel bases are not aligned with each other. (That is, it works for oblique prisms, too.)

Note that the cone, a pointed version of a cylinder, has 1/3 the volume. This is true also of any pointed objects in which the horizontal dimensions are proportional to the vertical dimensions*. (That is, this formula (1/3Bh), works for any right- or oblique pyramid-like object.)

__

* in this discussion, we have assumed the base is in a horizontal plane, and the height is measured vertically from that plane. Of course, any orientation is possible.

4 0
3 years ago
What is the solution of the equation 4p/6+27
anyanavicka [17]
The answer is 36 I'm pretty sure
7 0
3 years ago
Solve each quadratic equation by factoring. <br> Show steps pls<br> 8x^2 - 4x = 2x +9
saw5 [17]

Answer:

hope these help........

4 0
3 years ago
Read 2 more answers
One week a company filled 546 boxes with widgets each box held 38 widgets how many widgets did the company pack in boxes that we
Romashka [77]

Answer:

20748

Step-by-step explanation:

546 times 38

5 0
3 years ago
What are the solutions of the equation 3x^2+6x-24=0
Alekssandra [29.7K]

Answer:

x = - 4, x = 2

Step-by-step explanation:

Given

3x² + 6x - 24 = 0 ( divide through by 3 )

x² + 2x - 8 = 0 ← in standard form

(x + 4)(x - 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

x - 2 = 0 ⇒ x = 2

5 0
3 years ago
Other questions:
  • Find the missing angle measure A=51°, B=82°, C=5x+2
    11·1 answer
  • Circled one please?
    12·2 answers
  • HELP PLEASE!!!
    11·2 answers
  • Which of the following is a root of the polynomial shown below f(x)=x^3+2x^2-x-2
    11·2 answers
  • What is the domain of the function in the graph above?​
    15·1 answer
  • Whats the volume of the cylinder? Round your answer to the nearest hundred the top is B the left side of the cylinder is 13cm th
    14·1 answer
  • What is the pressure in atmospheres exerted by a 0.500 mole sample of nitrogen gas in a 10.0 L container at 25.0°C?
    10·1 answer
  • -24&lt;41<br>Adevarat sau fals?​
    11·2 answers
  • What is the slope of the line shown below?
    15·2 answers
  • Pls answer this i need help
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!