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3 years ago

There are 12 boys and 16 girls in a classroom. Which represents the simplified ratio of girls to students in the classroom?

1 answer:

4 0

We know that there are 16 girls. That is the first part of the ratio. Now, it says girls to students, which mean you have to add up the total of girls and boys together. 12+16=28. There are 28 students in total. Now, you have the ratio of 16:28. But, it says simplified...so we need to divide both sides of the ratio by a number. Let's choose 4 because 4 can go both into 16 and 28. 16/4=4. 28/4=7. So, the simplified ratio of girls to students in the classroom is 4:7.

Hope this helped!

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Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

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$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

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