Select all the values of x that make x + 3

Changing the mean and standard deviation of a Normal distribution by a moderate amount can greatly change the percent of observa

sweet-ann [11.9K]

Answer:

a) $P(X>750)=P(\frac{X-\mu}{\sigma}>\frac{750-\mu}{\sigma})=P(Z1.798)$

$P(Z>1.798)=1-P(z$

f. 3.59 %

b) $P(X>750)=P(\frac{X-\mu}{\sigma}>\frac{750-\mu}{\sigma})=P(Z2.21)$

$P(Z>2.21)=1-P(Z$

d. 1.36 %

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the scores of men of a population, and for this case we know the distribution for X is given by:

$X \sim N(527,124)$

Where $\mu=65.5$ and $\sigma=2.6$

We are interested on this probability

$P(X>750)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>750)=P(\frac{X-\mu}{\sigma}>\frac{750-\mu}{\sigma})=P(Z1.798)$

And we can find this probability using the complement rule and with the normal standard distribution table or excel:

$P(Z>1.798)=1-P(Z$

So then the correct answer for this case would be:

f. 3.59 %

Part b

Let X the random variable that represent the scores of women's of a population, and for this case we know the distribution for X is given by:

$X \sim N(496,115)$

Where $\mu=496$ and $\sigma=115$

We are interested on this probability

$P(X>750)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>750)=P(\frac{X-\mu}{\sigma}>\frac{750-\mu}{\sigma})=P(Z2.21)$

And we can find this probability using the complement rule and with the normal standard distribution table or excel:

$P(Z>2.21)=1-P(Z$

So then the correct answer for this case would be:

d. 1.36 %

7 0

2 years ago

Please help –8 = c /9 c=

kramer

Hey there! I'm happy to help!

We want to get c all by itself on one side of the equation. Usually variables go on the left side, so let's flip the equation around.

c/9=-8

If we multiply c/9 by 9, the 9 will cancel out because if you divide by 9 and then multiply by 9 it just equals 1. We can do this to isolate the c, but whatever you do to one side of the equation, you have to do to the other. So, we multiply both sides by 9.

c/9×9=-8×9

c=-72

Have a wonderful day! :D

4 0

3 years ago

Read 2 more answers

Is 4.110 smaller or bigger than 4.10

Ivenika [448]

4,110 is greater than 4.10 because 4,110 has more numbers while 4.10 and still no and also a matter of tenths :)

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2 years ago

Write the Recursive Rule for the sequence:

skad [1K]

A formula is recursive if it expresses the term $a_n$ in terms of the previous one(s) $a_{n-1},\ a_{n-2},\ \ldots,\ a_1$

In this case, every term is 7 more than the previous one, so the formula for $a_n$ will only involve $a_{n-1}$ :

$a_n = a_{n-1} + 7$

In fact, this formula is simply saying: for every index $n$ , the term with that index is 7 more than the term before.

Also, we have to specify the starting point (otherwise we would go backwards indefinitely), so the complete recursive formula is

$a_n = a_{n-1} + 7,\quad a_1 = 2$

which means: start with 2 and generate every other term by adding 7 to the previous one.

5 0

3 years ago

A certain species of tree grows an average of 3.1 cm per week. Write an equation for the sequence that represents the weekly hei

Allisa [31]

Y=3.1x+400 The x is how much it grows per week and the 400 is where it started at. the y is how tall it is after x weeks

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2 years ago

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Select all the values of x that make x + 3 > 5 true.