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2 years ago

9

The balance in your bank account is $720.50. You use your debit card for purchases of $45, $82, and $22.25. Then, you deposit $9

8.45 in the account. What is the new balance of your account?

1 answer:

myrzilka [38]2 years ago

7 0

Answer:

669 dollars and 70 cents

Step-by-step explanation:

just minus all the money spent and add the money added

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Plz help me !!!!!!!!!!!

liberstina [14]

Answer: a) -240

<u>Step-by-step explanation:</u>

$2\sqrt{-32}\cdot 5\sqrt{-18}\\\\=2\cdot 5\sqrt{-32\cdot -18}\\\\=10\sqrt{-1\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot -1\cdot 2\cdot 3\cdot 3}\\\\\\=10(-1\cdot 2\cdot 2\cdot 2\cdot 3)\\\\=10(-24)\\\\=\boxed{-240}$

4 0

3 years ago

The box-and-whisker plot represents the lengths (in minutes) of movies being shown at a theater.

GaryK [48]

Answer:

20

Step-by-step explanation:

130-110

Q3-Q1=IQR

Hope this helps!

3 0

1 year ago

Read 2 more answers

What is the slope of the line shown below?

Ivan

We can use the points (-4, 3) and (3, 1) to solve.

Slope formula: y2-y1/x2-x1

1-3/3-(-4)

-2/7

Therefore, the answer is C

Best of Luck!

6 0

2 years ago

Read 2 more answers

Someone please help me with this lol… have no idea what I’m doing

Sholpan [36]

Given:

$\cos \theta =\dfrac{3}{5}$

$\sin \theta$

To find:

The quadrant of the terminal side of $\theta$ and find the value of $\sin\theta$ .

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

$\cos \theta =\dfrac{3}{5}$

$\sin \theta$

Here cos is positive and sine is negative. So, $\theta$ must be lies in Quadrant IV.

We know that,

$\sin^2\theta +\cos^2\theta =1$

$\sin^2\theta=1-\cos^2\theta$

$\sin \theta=\pm \sqrt{1-\cos^2\theta}$

It is only negative because $\theta$ lies in Quadrant IV. So,

$\sin \theta=-\sqrt{1-\cos^2\theta}$

After substituting $\cos \theta =\dfrac{3}{5}$ , we get

$\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}$

$\sin \theta=-\sqrt{1-\dfrac{9}{25}}$

$\sin \theta=-\sqrt{\dfrac{25-9}{25}}$

$\sin \theta=-\sqrt{\dfrac{16}{25}}$

$\sin \theta=-\dfrac{4}{5}$

Therefore, the correct option is B.

6 0

2 years ago

Julia is casting a play with 4 main roles. Six students

aev [14]

Using the combination formula, it is found that Julia can take 15 combinations.

<h3>What is the combination formula?</h3>

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by:

$C_{n,x} = \frac{n!}{x!(n-x)!}$

For this problem, 4 students are taken from a set of 6, hence the number of combinations is given as follows:

$C_{6,4} = \frac{6!}{4!2!} = 15$

More can be learned about the combination formula at brainly.com/question/25821700

#SPJ1

7 0

1 year ago