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iVinArrow [24]
2 years ago
11

Given triangle MNK below, find sin M/ Cos K

Mathematics
1 answer:
meriva2 years ago
8 0

Answer:

The Answer is A

Step-by-step explanation:

its A I got it right

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Chris plotted 3 points on the graph of the equation y=2x. Which coordinates name the points on Chris’s graph?
Makovka662 [10]

Answer:

(0,0) (2,4) (-2,-4)

Step-by-step explanation:

8 0
2 years ago
Peter and Henry went to the movies Peter bought the two Movie tickets for 7 dollars each. How much did he spend for the movie ti
ivann1987 [24]

Answer:

tickets: $14

popcorn: $10

total: $24

Step-by-step explanation:

2 movie tickets at $7 each is 2*7 which is $14

2 buckets of popcorn at $5 each is 2*5 which is $10

adding these together we get a total spending of $24

3 0
2 years ago
What is the probability that both spinners land on red or orange?
yawa3891 [41]

Answer:

A, the probability is 1/9. you get this because you multiply the probabilities

in this example its 1/3 times 1/3 so you get 1/9

Step-by-step explanation:

5 0
3 years ago
Find gradient <br><br>xe^y + 4 ln y = x² at (1, 1)​
cricket20 [7]

xe^y+4\ln y=x^2

Differentiate both sides with respect to <em>x</em>, assuming <em>y</em> = <em>y</em>(<em>x</em>).

\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}

\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x

\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

Solve for d<em>y</em>/d<em>x</em> :

e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x

\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}

If <em>y</em> ≠ 0, we can write

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}

At the point (1, 1), the derivative is

\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}

4 0
3 years ago
Find the scale factor of the similar polygons. Simplify your answer. (Hint: New/Old)
Alenkasestr [34]
1.5 :) :) :) :) :) :)
7 0
2 years ago
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