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3 years ago

What is 19:48 converted into regular time

Mathematics

2 answers:

damaskus [11]3 years ago

7 0

7:48 pm when converted into regular time.

ira [324]3 years ago

6 0

In standard 12-hour time rather than 24-hour military time 19:48 would be known as 7:48 pm.

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Please dont ignore, Need help!!! Use the law of sines/cosines to find..

Ket [755]

Answer:

16. Angle C is approximately 13.0 degrees.

17. The length of segment BC is approximately 45.0.

18. Angle B is approximately 26.0 degrees.

15. The length of segment DF "e" is approximately 12.9.

Step-by-step explanation:

By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.

For triangle ABC:

$\sin{A} = \sin{103\textdegree{}}$ ,
The opposite side of angle A $a = BC = 26$ ,
The angle C is to be found, and
The length of the side opposite to angle C $c = AB = 6$ .

$\displaystyle \frac{\sin{C}}{\sin{A}} = \frac{c}{a}$ .

$\displaystyle \sin{C} = \frac{c}{a}\cdot \sin{A} = \frac{6}{26}\times \sin{103\textdegree}$ .

$\displaystyle C = \sin^{-1}{(\sin{C}}) = \sin^{-1}{\left(\frac{c}{a}\cdot \sin{A}\right)} = \sin^{-1}{\left(\frac{6}{26}\times \sin{103\textdegree}}\right)} = 13.0\textdegree{}$ .

Note that the inverse sine function here $\sin^{-1}()$ is also known as arcsin.

By the law of cosine,

$c^{2} = a^{2} + b^{2} - 2\;a\cdot b\cdot \cos{C}$ ,

where

$a$ , $b$ , and $c$ are the lengths of sides of triangle ABC, and
$\cos{C}$ is the cosine of angle C.

For triangle ABC:

$b = 21$ ,
$c = 30$ ,
The length of $a$ (segment BC) is to be found, and
The cosine of angle A is $\cos{123\textdegree}$ .

Therefore, replace C in the equation with A, and the law of cosine will become:

$a^{2} = b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}$ .

$\displaystyle \begin{aligned}a &= \sqrt{b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}}\\&=\sqrt{21^{2} + 30^{2} - 2\times 21\times 30 \times \cos{123\textdegree}}\\&=45.0 \end{aligned}$ .

For triangle ABC:

$a = 14$ ,
$b = 9$ ,
$c = 6$ , and
Angle B is to be found.

Start by finding the cosine of angle B. Apply the law of cosine.

$b^{2} = a^{2} + c^{2} - 2\;a\cdot c\cdot \cos{B}$ .

$\displaystyle \cos{B} = \frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}$ .

$\displaystyle B = \cos^{-1}{\left(\frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}\right)} = \cos^{-1}{\left(\frac{14^{2} + 6^{2} - 9^{2}}{2\times 14\times 6}\right)} = 26.0\textdegree$ .

For triangle DEF:

The length of segment DF is to be found,
The length of segment EF is 9,
The sine of angle E is $\sin{64\textdegree}}$ , and
The sine of angle D is $\sin{39\textdegree}$ .

Apply the law of sine:

$\displaystyle \frac{DF}{EF} = \frac{\sin{E}}{\sin{D}}$

$\displaystyle DF = \frac{\sin{E}}{\sin{D}}\cdot EF = \frac{\sin{64\textdegree}}{39\textdegree} \times 9 = 12.9$ .

7 0

3 years ago

PLSSS I NEED HELP VERY QUICKLY!!!!!!!!!!

dangina [55]

Answer:

6.7

Step-by-step explanation:

$\sqrt(3 ^{2} + 6 ^{2} )$

$\sqrt{45} \\ \\ = 6.7cm$

3 0

2 years ago

Write a division problem that has a quotient of 1/20

alexdok [17]

Answer:

5 divided by 100

Step-by-step explanation

5 divided by 100 is 0.05 but as a fraction, it's 1/20

6 0

3 years ago

Help please. this is area and the shaded region.

nalin [4]

put the varible on the shaded half

3 0

3 years ago

Read 2 more answers

Emil is running a lemonade stand. He sells half of his lemonade in the morning, a quarter of what was left at lunchtime, and a t

masya89 [10]

Emil starts the day with <u>16 liters</u> of lemonade if he is left with 4 liters by the end of the day. Computed using the fractional values given.

Let the initial quantity of lemonade with Emil be x liters.

Quantity sold by Emil in the morning = Half of his lemonade = (1/2)x liters, that is half fraction of x.

Quantity left with Emil = x - x/2 = x/2 liters, that is half fraction of x.

Quantity sold by Emil at lunchtime = Quarter of what was left = (1/4)(x/2) liters = x/8 liters, that is the one-eight fraction of x.

Quantity left with Emil = x/2 - x/8 = 3x/8 liters, that is the three-eight fraction of x.

Quantity sold by Emil in the afternoon = One-third of what was left = (1/3)(3x/8) liters = x/8 liters, that is the one-eight fraction of x.

Quantity left with Emil = 3x/8 - x/8 = x/4 liters, that is the quarter fraction of x.

Now, we are said that Emil closes for the day with 4 liters remaining.

Therefore, x/4 = 4, or, x = 4*4 = 16 liters.

Therefore, Emil started the day with 16 liters of lemonade.

Learn more about fractions at

brainly.com/question/11562149

#SPJ10

6 0

2 years ago