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11111nata11111 [884]
1 year ago
15

Hardest math question ever

Mathematics
1 answer:
ohaa [14]1 year ago
5 0
<h2>Part a)</h2>

You can name planes by one letter or using three points belonging to it that are <u>not</u> on the same line.

Another name for plane X could be:

  • Plane ABF, Plane BCF or Plane ACF. You may also get different names by reordering the three letters.

<h2>Part b)</h2>

Coplanar means 'on the same plane'.

The points on the same plane as point A are:

  • B, C and F.

<h2>Part c)</h2>

Collinear means 'on the same line'.

Other points on the same line as point C are:

  • A or B.

<h2>Part d)</h2>

The line that intersects ED is:

  • AC, it can be also named AB or BC.

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How do you make a table for a function whose graph has a y-intercept of 4 and a slope of 2
ch4aika [34]
Point of Y intercept is (0,4)
Y1-Y2=m(X1-X2)
Plug in x,y into X2, Y2 m=slope

y-4=2(x-0)
y-4=2x
y=2x+4
Table
Plug in for x and y
x. y
0. 4
1. 6
2. 8
7 0
3 years ago
NEED HELP NOW!!!
Amiraneli [1.4K]

<em><u>D.</u></em><em><u> </u></em>

<em><u>Explanation</u></em><em><u>:</u></em>

<em><u>a landscape of farmland bisected by long straight roads"</u></em>

<em><u>divide into two parts.</u></em>

<em><u>hope</u></em><em><u> I</u></em><em><u> help</u></em><em><u> you</u></em><em><u> ☺️</u></em><em><u>❤️</u></em>

<em><u>:</u></em><em><u>)</u></em><em><u> </u></em><em><u> </u></em><em><u>:</u></em><em><u>></u></em>

8 0
2 years ago
Simple algebra need help!!!​
nadezda [96]

Answer:

12.85 m

Step-by-step explanation:

First, you have to find the arc length of the sector. To do that, use the formula for arc length.

\frac{x}{360}  \times \pi \: d

Since the figure is a semicircle, we know the central angle is 180, so plug that in for x. We also know the diameter, which is 5. So plug that in for d. Once you get the arc length, add 5 to it. 5 is the diameter and is part of the perimeter

5 0
3 years ago
Please someone actually help with this I don't understand how.​
tigry1 [53]

Answer:

Scatter plot

Step-by-step explanation:

Answer is 5

8 0
3 years ago
Axis of sym: x =
marta [7]

Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic function
  • PEMDAS
<h3>let's solve:</h3>

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

  • to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

  • y=a(x-h)²+k

therefore

  • y=a(x-(-1))²+4
  • y=a(x+1)²+4

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

3 = a(1 {)}^{2}  + 4

simplify exponent:

3 =  a + 4

therefore

a =  - 1

our vertex form of quadratic equation is

  • y=-(x+1)²+4

let's simplify it to standard form

simplify square:

y =  - ( {x}^{2}  + 2x + 1)  + 4

simplify parentheses:

y =  -  {x}^{2}  - 2x - 1 + 4

simplify addition:

y =  -  {x}^{2}  - 2x + 3

therefore our answer is D)y=-x²-2x+3

the domain of the function

x\in \mathbb{R}

and the range of the function is

y\leqslant 4

zeroes of the function:

-  {x}^{2}  - 2x + 3 = 0

\sf divide \: both \: sides \: by \:  - 1

{x}^{2}  + 2x - 3 = 0

\implies \:  {x}^{2} +   3x  - x  +  3 = 0

factor out x and -1 respectively:

\sf \implies \: x(x + 3)   - 1(x  + 3 )= 0

group:

\implies \: (x - 1)(x + 3) = 0

therefore

\begin{cases} x_{1} = 1 \\  x_{2}  =  - 3\end{cases}

4 0
3 years ago
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