3 years ago

How do you find the remainder of (x^3-6x^2-9x+3) / (x-3)

1 answer:

4 0

x^3-6x^2-9x+3 | x-3
-x^3+3x^2 x^2-3x-18
\\\\\ -3x^2-9x+3
+3x^2-9x
\\\\\\ -18x+3
+18x-54
\\\\\ -51

Q(x) = x^2-3x-18
R(x) = -51

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