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Oduvanchick [21]
3 years ago
13

How do you find the remainder of (x^3-6x^2-9x+3) / (x-3)

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0
 x^3-6x^2-9x+3     | x-3
-x^3+3x^2               x^2-3x-18
 \\\\\ -3x^2-9x+3
      +3x^2-9x
         \\\\\\ -18x+3 
                 +18x-54
                  \\\\\ -51

Q(x) = x^2-3x-18
R(x) = -51
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Sum-of-the-year digits = (remaining useful life / sum of the years ) x  (Cost of asset - Salvage value)

Depreciation expense in year 1:

Sum of the years = 1 +2 +3 +4 + 5 + 6 + 7 + 8 + 9 + 10+ 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 210

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Book value = 79600 - 7200 - 6840 = $65,560

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