All categories

3 years ago

How do you find the remainder of (x^3-6x^2-9x+3) / (x-3)

1 answer:

4 0

x^3-6x^2-9x+3 | x-3
-x^3+3x^2 x^2-3x-18
\\\\\ -3x^2-9x+3
+3x^2-9x
\\\\\\ -18x+3
+18x-54
\\\\\ -51

Q(x) = x^2-3x-18
R(x) = -51

You might be interested in

NEED HELP ASAP!!!!!

pashok25 [27]

D. Because 5 and 5 could land on any

6 0

3 years ago

Read 2 more answers

Furnace repairs Rj's plumbing charges $55 plus $40 per hour for emergency service. Gary remembers being billed over $150 for an

bulgar [2K]

You set it up as a y=mx+b problem 150=55x+40 then you subtract 40 from 150 making 110=55x so x=2

6 0

3 years ago

Tennis elbow is thought to be aggravated by the impact experienced when hitting the ball. The article "Forces on the Hand in the

Gnoma [55]

Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.

n₁= 6

X[bar]₁= 40.29 N

S₁= 11.29

Sample 2: Intermediate players

X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.

n₂= 8

X[bar]₂= 21.40

S₂= 8.30

Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

$t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}$

$Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66$

$t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62$

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

I hope this helps!

3 0

4 years ago

Following ungrouped data of Sales of a company (in millions) is available

Diano4ka-milaya [45]

Lol no one is going to work that out just copy and paste into an online calculator good luck

3 0

3 years ago

A stadium has 50,000 seats. Seats sell for $35 in section A, $30 in section B, and $25 in section C. The number of seats in sect

Dennis_Churaev [7]

The answer is Section A. has 25,000 seats,section B. has 12,500 seats and section C. has 12,500 seats.

How I got to the answer.
I divided 50,000÷4=12,500 then I multiplied 12,500×2=25,000.
I hope this helps.

3 0

3 years ago