Ask question

Ask question

All categories

3 years ago

7

On a certain hot summer's day, 195 people used the public swimming pool. The daily prices are $1.75 for children and $2.25 for

adults. The receipts for admission totaled $383.75. How many children and how many adults swam at the public pool that day?

1 answer:

Marina CMI [18]3 years ago

8 0

Answer:

3x-x+2=4

Step-by-step explanation:

Children = x

Adults = y

x + y = 754...1

1.50x + 2.25y = 1422...2

Multiply (1) by 2.25

2.25x + 2.25y = 1696.50...3

1.50x + 2.25y = 1422...2

Subtract (2) from (3)

0.75x = 274.50

x = 366

Substitute x = 366 in (1)

x + y = 754

366 + y = 754

y = 388

366 children and 388 adults swam at the pool.

You might be interested in

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

--------------------------------------------------------------------------------------

$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$

= 1 - 18x + 135x² - 540x³ + 1215 $x^{4}$ - 1458 $x^{5}$ + 729 $x^{6}$

----------------------------------------------------------------------------------

Collecting like terms from both expressions

$(1+3x)^{6}$ + $(1-3x)^{6}$

= 2 + 270x² + 2430 $x^{4}$ + 1458 $x^{6}$

----------------------------------------------------

(2)

Using Pascal's triangle with n = 5

1 5 10 10 5 1

Decreasing powers of 1 from $1^{5}$ to $1^{0}$

Increasing powers of 2x from $(2x)^{0}$ to $(2x)^{5}$

$(1+2x)^{5}$

= 1. $1^{5}$ $(2x)^{0}$ + 5. $1^{4}$ $(2x)^{1}$ + 10. $1^{3}$ $(2x)^{2}$ + 10. $1^{2}$ $(2x)^{3}$ + 5. $1^{1}$ $(2x)^{4}$ + 1. $1^{0}$ $(2x)^{5}$

= 1 + 10x + 40x² + 80x³ + 80 $x^{4}$ + 32 $x^{5}$

8 0

3 years ago

6 yd 3 yd 8 yd equal what?

Kamila [148]

Hello!

Answer:

17 yards

Step-by-step explanation:

Hope this helps have a wonderful day! :3

7 0

2 years ago

Read 2 more answers

Solve for w: -4u-w = u+6w

wlad13 [49]

Answer:

A

Step-by-step explanation:

-4u - w = u + 6w

-4u = u + 7w (Add w to both sides)

-5u = 7w (Subtract u from both sides)

w = $-\frac{5u}{7}$ (Divide both sides by 7)

8 0

3 years ago

Read 2 more answers

Which expressions are equivalent to the one below?check all that apply. 21^x/3^x

mafiozo [28]

C and E and F are all the correct answers

7 0

3 years ago

Read 2 more answers

How many unique triangles can be made with 3,5,8

blondinia [14]

Answer

2 or 3

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers