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Schach [20]
3 years ago
6

What is the area of the triangle in the diagram?

Mathematics
2 answers:
dsp733 years ago
5 0

Answer:

The answer is the 2nd one

Step-by-step explanation:

mariarad [96]3 years ago
5 0

Answer:

(B)          

Step-by-step explanation:

Given: A triangle whose coordinates are (0,0), (x_{1},y_{1}) and (x_{2},y_{1}).

To find: The area of the triangle.

Solution: We know that Area of triangle=\frac{1}{2}{\times}base{\times}height.

Now, Base=\sqrt{(x_{2}-x_{1})^{2}+(y_{1}-y_{1})^{2}}

Base=(x_{2}-x_{1})

And height=\sqrt{(0-0)^2+(y_{1}-0)^2}

Height= y_{1}

Therefore, area of triangle= \frac{1}{2}{\times}(x_{2}-x_{1})}{\times}y_{1}

Area of triangle=\frac{1}{2}y_{1}(x_{2}-x_{1})}

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What is the value of x for the regular polygon shown below?<br> 2x + 4<br> 36
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Im not sure what your asking add more please
3 0
2 years ago
-6(2+n) is greater than 72
Hitman42 [59]

Answer:

n > -14

Step-by-step explanation:

Firstly, you use the distributive property;

-12 - 6n > 72

Then, since 12 is negative, you add 12 to both sides;

-12 - 6n > 72

+12           +12

-6n > 84

Then you divide both sides by -6 to get n > -14.


Shoot, hold on; this is an edit; did you mean that 72 is greater than -6(2 + n) or did you accidentally flip the sign in the picture? Hopefully I did what you needed.


5 0
3 years ago
Read 2 more answers
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Umnica [9.8K]

Answer:

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6 0
3 years ago
The age of a father is two less than seven times the age of his son in two years the sum of their ages will be 57 if the son's p
ASHA 777 [7]

Answer:

f = 7s -2

f  + s =53

Step-by-step explanation:

Given

Let

f = Father's age

s = Son's age

We'll solve this question, while reading through the instructions

From the first statement;

f is 2 less than 7 times s.

This means

f = 7s -2

In two years time, the father will be f +2 and the son will be s + 2

So, their sum is:

(f+2) + (s + 2) = 57

f + 2 + s + 2 =57

Collect like terns

f  + s =57-2-2

f  + s =53

So, the equations are:

f = 7s -2

f  + s =53

5 0
3 years ago
The perimeter of a quadrilateral (four-sides polygon) is 50 inches. The longest side is three times as long as the shortest side
kkurt [141]

The side lengths of quadrilateral are 21 inches; 11 inches; 11 inches; 7 inches.

<u>SOLUTION:</u>

Given, the perimeter of a quadrilateral (four-side polygon) is 50 inches.  

Let the length of shortest side be n inches.  The longest side is three times as long as the shortest side.  

That is, length of largest side = 3n inches

The other two sides are equally long and are 4 inches longer than the shortest side.  

Then, length of remaining two sides = 4 + n inches  

We have to find the length of all four sides.

Now, we know that, perimeter = 50 inches  

\begin{array}{l}{\rightarrow \text { Sum of all sides }=50} \\\\ {\rightarrow n+3 n+n+4+n+4=50} \\\\ {\rightarrow n+3 n+n+n=50-4-4} \\\\ {\rightarrow 6 n=42} \\\\ {\rightarrow n=7}\end{array}

So, length of sides will be,

7 \text { inches; } 3\times7=21 \text { inches; } 7+4=11 \text { inches; } 7+4=11 \text { inches. }

6 0
3 years ago
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