Question

Please help I will brainliest!! Really urgent!!

Answer 1

Answer:

$\frac{1}{6}$x-19

Step-by-step explanation:

$\frac{2}{3}$x-9-$\frac{1}{2}$x-10 = $\frac{2}{3}$x-$\frac{1}{2}$x-19

If you minus 9 and then minus 10, you are deducting 19 from the equation in total

$\frac{2}{3}$x-$\frac{1}{2}$x-19 = $\frac{4}{6}$x-$\frac{3}{6}$x-19

You would want to make the denominator of the fractions the same by multiplying the first fraction by 2, and the second fraction by 3 so that both denominators are 6.

$\frac{4}{6}$x-$\frac{3}{6}$x-19 = $\frac{1}{6}$x-19

Now that their denominators are the same, you can directly do the working for the numerators (4-3=1) and keep the denominator the same. Tada!