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Andreyy89
2 years ago
7

Order the decimal numbers from the smallest to the largest.

Mathematics
1 answer:
Naddika [18.5K]2 years ago
8 0

A: 0.1, 0.2, 0.3, 0.4, 0.6, 0.8

B: 0.01, 0.09, 0.23, 0.54, 0.79, 0.85

C: 1.13, 1.86, 1.93, 2.45, 3.67, 5.85

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What would be the answer for 24y =7
Marta_Voda [28]

Answer:

y=\frac{7}{24}

Step-by-step explanation:

24y = 7

Our primary objective here is to get y on it's own side, without any numbers attached.

Since a 24 is attached to the y, we have to divide the 24y by 24.

24y=7

\frac{24y}{24} = \frac{7}{24}

Remember that whatever we do to one side, we MUST do to the other.

y=\frac{7}{24}

Since \frac{7}{24} can't be simplified, that would be our answer.

Please let me know if you need help with anything else. :)

5 0
3 years ago
The vertex of the parabola below is at the point (1.-3). Which of the equations below could be the one for this parabola?
Ilia_Sergeevich [38]

Answer: Choice D. y = (x-1)^2 - 3

The vertex is (h,k) = (1,-3). So h = 1 and k = -3.

We have a = 1 as the leading coefficient.

Plug those values into the equation below

y = a(x-h)^2 + k

y = 1(x - 1)^2 + (-3)

y = (x - 1)^2 - 3

3 0
3 years ago
Read 2 more answers
7.6x = 64 is approximately 3.05.<br> is this the solution?
lisov135 [29]
7.6x = 64
x = 64/7.6
x = <span> <span> <span> 8.4210526316 </span> </span> </span>
So, 3.05 is NOT the solution

3 0
3 years ago
A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind t
Katyanochek1 [597]
The answer to this question:
One car probability 82/120
No car probability = 24/120
At least one car probability= 96/120

I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability)  is the opposite of (no car probability) In this case, the easier way is 
100% - (no car probability) = 120/120 - 24/120= 96/120

One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability) 
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

One car probability =  (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120
3 0
3 years ago
Write an equation of the line that has a slope of 2 and y-intercept 1 in slope-intercept form.
Vlada [557]
Y = mx + b

in this case m = 2 and b = 1 so
equation
y =2x + 1

hope this helps
4 0
3 years ago
Read 2 more answers
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