R^2=(x-6)^2+(y-4)^2
r^2=(6-2)^2+(4-1)^2, r^2=16+9=25
(x-6)^2+(y-4)^2=25
Take ln to both sides
ln 14^x = ln 5
then you'll get
x ln 14 = ln 5
divide both sides by ln 14
x = 0.6098533345
after rounding
x = 0.6099
You would multiply each kilogram amount by 2.2 to get the point equivalent.
9514 1404 393
Answer:
(√7)/3
Step-by-step explanation:
The relationship between tangent and cosine is ...
tan(α) = √(1/cos(α)² -1)
The cosine of the angle is given as 3/4, so the tangent is ...
tan(arccos(3/4)) = √(1/(3/4)² -1) = √(16/9 -1) = √(7/9)
tan(arccos(3/4)) = (√7)/3
Slope= Mx in y=Mx+b jrbdhendj
