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8090 [49]
3 years ago
6

I neeed youurr help please can u solve this ??

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
7 0

Answer:

sorry my brian aint working

Step-by-step explanation:

shtirl [24]3 years ago
3 0
That’s the same thing I’m doing too
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Simplify completely: the quantity 10 times x to the 6th power times y to the third power plus 20 times x to the third power time
eimsori [14]
Correct answer is D.

\frac{10x^6y^3 + 20x^3y^2}{5x^3y}
\\
\\ \text{common in the numerator is }
\\
\\ 10x^3y^2
\\
\\ \text{so}
\\
\\ \frac{10x^3y^2(x^3y + 2)}{5x^3y}
\\
\\ \text{cancel common factors... }
\\
\\ 2y(x^3y + 2) = 2x^3y^2 + 4y
6 0
3 years ago
A worm travels 1,250 millimeters.How many meters did the worm travel
vazorg [7]


The answer is 1.25 meters.

hope it helps

can you choose mine as the brainliest answer

5 0
3 years ago
(PLEASE HELP PLEASE!! IM GOING TO FAIL) PLEASE HELP ME WITH THESE QUESTIONS!! NOT JUST FOR ME FOR BRAIN! WHO WILL ANSWER FIRST?!
Lina20 [59]
1. A
2. should be 42?
3.???
4.27 apples left
5.B 1/4
7 0
3 years ago
The list below shows the Highlight in inches of the player on a man college basketball team
boyakko [2]

We have the data set:

{79, 83, 82, 78, 79, 77, 80, 73, 82, 72}

This data set has 10 items.

To complete the data summary is helpful to sort the data:

{72, 73, 77, 78, 79, 79, 80, 82, 82, 83}

The minimum value is 72.

<em>The quartile divides the data set in 4 parts. </em>

<em>The first quartile is the value for which 25% of the data is below.</em>

<em>The second quartile is the value for which 50% of the data is below. The second quartile is equivalent to the median.</em>

<em>The third quartile is the value for which 75% of the data is below.</em>

In this data set, as its size is a even number, the quartile fall between two positions, so we will calculate the average of this numbers.

The first quartile will fall in the position 0.25*10=2.5. Then we can calculate the 1st quartile as the average between the 2nd and 3rd number of the data set.

This values are 73 (2nd position) and 77 (3rd position), so the average is:

Q_1=\frac{73+77}{2}=75

We can repeat this with the other quartiles:

\begin{gathered} Q_2=M=\frac{79+79}{2}=79 \\ Q_3=\frac{82+82}{2}=82 \end{gathered}

Then:

The first quartile is 75.

The median (second quartile) is 79.

The third quartile is 82.

The maximum value is 83.

7 0
1 year ago
Steve rounds his favorite number to the nearest hundred to get 400.
Tcecarenko [31]

Answer:

whats the question???

8 0
3 years ago
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