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Sonbull [250]
3 years ago
7

In 2016 49% of all degrees granted were bachelors degrees if 1,920,718 students earned bachelors degrees how many total degrees

were granted that year
Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0

Answer:

<h2>3919832.65306</h2>

Step-by-step explanation:

This problem is focused on percentages.

Now given that 49% of a number is  1,920,718

we can say let the number be x

so 49% of x=  1,920,718

now expressing this problem mathematically we have

(49/100)*x=  1,920,718

0.49x= 1,920,718

divide both sides by 0.49 we have

x=  1,920,718/0.49

x= 3919832.65306

Therefore the total that were granted degree that year was 3919832.65306

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Nathan earns $1500 a week. Calculate his new weekly wage if he receives a pay rise of 20%
bazaltina [42]

Answer:

$1800

Step-by-step explanation:

1. Approanch

An easy way to calculate one's salary after they recive a raise is to, convert the percent that one's salary is increased into a decimal; divide the percent by 100. Then multiply the increase as a decimal by the original salary, to attain the amount the salary is raised by. Finally add the amount the salary is raised by to the original salary to find the new salary. A quicker way to do this is to convert the percent by the salary is increased into a decimal. Then add 1 to that number. Finally one will multiply that number by the original slary and get the new salary.

2. Solving

Original salary; 1500

Raise; 20%

<u>a. convert the raise as a percent into a decimal, then add 1</u>

20% = 0.2

0.2 + 1 = 1.2

<u>b. multiply the number by the original salary</u>

1.2 * 1500

1800

8 0
3 years ago
Read 2 more answers
Find all the solutions for the equation:
Contact [7]

2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0

Divide both sides by x^2\,\mathrm dx to get

2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}

Substitute v(x)=\dfrac{y(x)}x, so that \dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}. Then

x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}

x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}

x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}

The remaining ODE is separable. Separating the variables gives

\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x

Integrate both sides. On the left, split up the integrand into partial fractions.

\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}

\implies v^2+2v+1=a(v^2+1)+(bv+c)v

\implies v^2+2v+1=(a+b)v^2+cv+a

\implies a=1,b=0,c=2

Then

\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v

On the right, we have

\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C

Solving for v(x) explicitly is unlikely to succeed, so we leave the solution in implicit form,

\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C

and finally solve in terms of y(x) by replacing v(x)=\dfrac{y(x)}x:

\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C

\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C

\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}

7 0
3 years ago
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Sophie [7]
The answer you're looking for is A. a number subtracted from 9
8 0
3 years ago
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9. If y = 30 when x = 7, find x when y = 12.​
Marianna [84]
I have my work at the bottom but to explain you have to divide 30/12, and I got 2.5. That means 30 is 2.5 times bigger than 12. Because we have to find x, we have to divide 7/2.5, to find what is 2.5 times smaller than 7. That’s 2.8. So, x= 2.8

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3 years ago
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zysi [14]

Answer:

1 surds

2 fraction

3 decimal

4 negative

5 positive

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3 years ago
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