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3 years ago

12

A forest covers 51,000 acres. A survey finds that 0.6% of the forest is old-growth trees. How many acres of old-growth trees

are there?

1 answer:

RSB [31]3 years ago

3 0

306. A thank you or brainliest is always appreciated!

You might be interested in

Not sure how to do this *look at the picture*

torisob [31]

30 + 20 + 30 + 20 = 100

30 x 10% = 3 + 30 = 33

20 x 5% = 1 + 20 = 21

33 + 21 + 33 + 21 = 108

100 / 108 = 0.925925926 = 0.93 = 93%

100% - 93% = 7%

7% increase

4 0

3 years ago

Are these ratios equivalent?

Debora [2.8K]

<h3>Answer: Yes</h3>

========================================================

Explanation

The ratio 8:10 simplifies to 4:5 when you divide both parts by 2.

The ratio 16:20 simplifies to 4:5 when you divide both parts by 4

Therefore the two ratios 8:10 and 16:20 are both equal 4:5, so they are equal to one another.

------------

Put another way,

(8 large)/(10 small) = (16 large)/(20 small)

8/10 = 16/20

8*20 = 10*16 ... cross multiply

160 = 160

We get a true equation, so the first equation is true as well.

This shows the ratios are equivalent.

-------------

Or you could have...

(8 large)/(16 large) = (10 small)/(20 small)

8/16 = 10/20

8*20 = 16*10

160 = 160

We get the same conclusion as before.

3 0

3 years ago

Find the difference between and 8/15 - -(2/3). Show all calculations in your final answer please!! :)

sasho [114]

Answer:

$\boxed{\dfrac{34}{15}}$

Step-by-step explanation:

$\text{Use }\LaTeX$ (ﾉ◕ヮ◕)ﾉ*:･ﾟ✧

$\dfrac{8}{5} - - \left(\dfrac{2}{3}\right)$

$\dfrac{8}{5} - \left[-\dfrac{2}{3}\right]$

$\dfrac{8}{5} +\dfrac{2}{3}$

$\dfrac{8(3)}{5(3)} +\dfrac{2(5)}{3(5)}$

$\dfrac{24}{15} +\dfrac{10}{15}$

$\boxed{\dfrac{34}{15}}$

3 0

3 years ago

Read 2 more answers

a reciple calls for 6 cup of water and 4 cups of flour if the reciple is increased to use 6 cups of flour how much water shoud b

Setler79 [48]

Ratio and propoertion
6 to 4=x to 6
6:4=x:6
6/4=x/6
3/2=x/6
mutiply both sides by 6
18/2=x
9=x
answer is 9 cups of water

5 0

3 years ago

Find the function y = f(t) passing through the point (0, 18) with the given first derivative.

monitta

Answer:

$\displaystyle y = \frac{t^2}{16} + 18$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

<u>Algebra I</u>

Functions
Function Notation
Coordinates (x, y)

<u>Calculus</u>

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (0, 18)

$\displaystyle \frac{dy}{dt} = \frac{1}{8} t$

<u>Step 2: Find General Solution</u>

<em>Use integration</em>

[Derivative] Rewrite: $\displaystyle dy = \frac{1}{8} t\ dt$
[Equality Property] Integrate both sides: $\displaystyle \int dy = \int {\frac{1}{8} t} \, dt$
[Left Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \int {\frac{1}{8} t} \, dt$
[Right Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle y = \frac{1}{8}\int {t} \, dt$
[Right Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \frac{1}{8}(\frac{t^2}{2}) + C$
Multiply: $\displaystyle y = \frac{t^2}{16} + C$

<u>Step 3: Find Particular Solution</u>

Substitute in point [Function]: $\displaystyle 18 = \frac{0^2}{16} + C$
Simplify: $\displaystyle 18 = 0 + C$
Add: $\displaystyle 18 = C$
Rewrite: $\displaystyle C = 18$
Substitute in <em>C</em> [Function]: $\displaystyle y = \frac{t^2}{16} + 18$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Integration

Book: College Calculus 10e

4 0

2 years ago