Question

GJ is a midsegment of triangle DEF, and HK is a midsegment of triangle GFJ. What is the length of HK?

Answer 1

Answer:

Option B) 4 centimeters

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the value of n

we know that

a) GJ is a midsegment of triangle DEF

then

G is the midpoint segment DF and J is the midpoint segment EF

DG=GF and EJ=JF

b) HK is a midsegment of triangle GFJ

then

H is the midpoint segment GF and K is the midpoint segment JF

GH=HF and JK=KF

In this problem we have

HF=7 cm

so

GH=7 cm

GF=GH+HF ----> by addition segment postulate

GF=7+7=14 cm

Remember that

DG=GF

substitute the given values

$2n-1=14$

solve for n

$2n=14+1$

$2n=15$

$n=7.5\ cm$

step 2

Find the length of GJ

we know that

The Midpoint Theorem states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side

so

$GJ=\frac{1}{2}DE$

we have

$GE=2n+1=2(7.5)+1=16\ cm$

substitute

$GJ=\frac{1}{2}16=8\ cm$

step 3

Find the length of HK

we have that

$HK=\frac{1}{2}GJ$ ----> by the midpoint theorem

we have

$GJ=8\ cm$

substitute

$HK=\frac{1}{2}8=4\ cm$