Three consecutive odd numbers have a sum of 75. What is the greatest number?

1 answer:

3 0

Let us assume the first odd number = x
Then the second consecutive odd number = x + 2
The third consecutive odd number = x + 4
The addition of the three consecutive odd numbers = 75
Then we can write the equation as
x + x + 2 + x + 4 = 75
3x + 6 = 75
3x = 75 - 6
3x = 69
x = 69/3
   = 23
Then
The greatest odd number in the question = X + 4
      = 23 + 4
   = 27
So the greatest odd number in the question is 27.

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What is the rate of change in decimal form for the points (1,5) (0,-3)

seraphim [82]

Answer:

The rate of change between (1, 5) and (0, -3) would be 8.0.

Step-by-step explanation:

"What is the rate of change between these two points" is the same as asking "what is the slope between these two points".

We are given the two points (1, 5) and (0, -3) and we are asked to find the rate of change (slope) between these two points. To do this, we could use the slope formula to find the rate of change between the two points. The slope formula is:

$\frac{y_2-y_1}{x_2-x_1}$

where (x₂, y₂) and (x₁, y₁) are the two points that we are trying to find the slope between.

Lets make (x₂, y₂) = (1, 5) and (x₁, y₁) = (0, -3). (It does not matter which is (x₂, y₂) and which is (x₁, y₁)). Now plug (x₂, y₂) = (1, 5) and (x₁, y₁) = (0, -3) into the equation:

$\frac{5-(-3)}{1-0} =\frac{8}{1}=8$

8 = 8.0, so the answer would be 8.0.

The rate of change between the two points would be 8.0.

I hope you find my answer helpful. :)

3 0

3 years ago

A colony of bacteria is grown under ideal conditions in a laboratory so that the population increases exponentially with time. A

Naddik [55]

Answer:

Initial bacterias = 6006000

Altought I believe is safe to assume that the values were 192,000 and 384,000 instead of 192,192,000 and 384,384,000, in that case the initial bacterias is 6000

Step-by-step explanation:

A exponential growth follows this formula:

Bacterias = C*rⁿ

C the initial amount

r the growth rate

n the number of time intervals

Bacterias (55 hours) = 192,192,000

Bacterias (66 hours) = 384,384,000

$Bacterias(55hours)=C*r^{{\frac{55-t}{t}}} \\Bacterias (66hours) = C*r^{\frac{66-t}{t}}}$

If you divide both you can get the growth rate:

$\frac{Bacterias (66hours)}{Bacterias(55hours)}=\frac{C*r^{\frac{66-t}{t}}}{C*r^{{\frac{55-t}{t}}}} \\\frac{384,384,000}{192,192,000} =r^{\frac{66-t}{t} -\frac{55-t}{t} } \\2 =r^{\frac{11}{t}}$