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3 years ago

Someone plz help me!

Mathematics

1 answer:

Verdich [7]3 years ago

3 0

Answer:

56.25 cm

Step-by-step explanation:

your teacher wrote the approach already : the law of sines.

in our example we have

sin(28)/27 = sin(102)/c

c×sin(28)/27 = sin(102)

c×sin(28) = 27×sin(102)

c = 27×sin(102)/sin(28) = 27×0.98/0.47 = 56.25 cm

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Help asappppp tyyy

True [87]

Given:

Compound shape

To find:

The area of the compound shape.

Solution:

The compound shape is splitted into two parallelograms.

<u>Bottom parallelogram:</u>

Base = 7.5 cm

Height = 5 cm

Area of the parallelogram = base × height

= 7.5 × 5

= 37.5 cm²

The area of the Bottom parallelogram 37.5 cm².

<u>Top parallelogram:</u>

Base = 7.5 cm

Height = 4.5 cm

Area of the parallelogram = base × height

= 7.5 × 4.5

= 33.75 cm²

The area of the top parallelogram 33.75 cm².

Compound shape = 37.5 + 33.75

= 71.25 cm²

The area of the compound shape is 71.25 cm².

7 0

3 years ago

4.9cm cubed to mm cubed. Help me asap. google is a liar

Lunna [17]

It is 4900mm^3 because there are 1000mm^3 in one 1cm^3.
If you do 10^3 (10 mm) it gives you 1000mm^3.

Hope this helps.

8 0

3 years ago

Indicate the equation of the given line in standard form. Show all your work for full credit. the line containing the median of

alukav5142 [94]

Answer:

* The equation of the median of the trapezoid is 10x + 6y = 39

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) , (x2 , y2) is

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

- The mid point of the line whose end point are (x1 , y1) , (x2 , y2) is

$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

- The standard form of the linear equation is Ax + BC = C, where

A , B , C are integers and A , B ≠ 0

- The median of a trapezoid is a segment that joins the midpoints of

the nonparallel sides

- It has two properties:

# It is parallel to both bases

# Its length equals half the sum of the base lengths

* Lets solve the problem

- The trapezoid has vertices R (-1 , 5) , S (! , 8) , T (7 , -2) , U (2 , 0)

- Lets find the slope of the 4 sides two find which of them are the

parallel bases and which of them are the non-parallel bases

# The side RS

∵ $m_{RS}=\frac{8-5}{1 - (-1)}=\frac{3}{2}$

# The side ST

∵ $m_{ST}=\frac{-2-8}{7-1}=\frac{-10}{6}=\frac{-5}{3}$

# The side TU

∵ $m_{TU}=\frac{0-(-2)}{2-7}=\frac{2}{-5}=\frac{-2}{5}$

# The side UR

∵ $m_{UR}=\frac{5-0}{-1-2}=\frac{5}{-3}=\frac{-5}{3}$

∵ The slope of ST = the slop UR

∴ ST// UR

∴ The parallel bases are ST and UR

∴ The nonparallel sides are RS and TU

- Lets find the midpoint of RS and TU to find the equation of the

median of the trapezoid

∵ The median of a trapezoid is a segment that joins the midpoints of

the nonparallel sides

∵ The midpoint of RS = $(\frac{-1+1}{2},\frac{5+8}{2})=(0,\frac{13}{2})$

∵ The median is parallel to both bases

∴ The slope of the median equal the slopes of the parallel bases = -5/3

∵ The form of the equation of a line is y = mx + c

∴ The equation of the median is y = -5/3 x + c

- To find c substitute x , y in the equation by the coordinates of the

midpoint of RS

∵ The mid point of Rs is (0 , 13/2)

∴ 13/2 = -5/3 (0) + c

∴ 13/2 = c

∴ The equation of the median is y = -5/3 x + 13/2

- Multiply the two sides by 6 to cancel the denominator

∴ The equation of the median is 6y = -10x + 39

- Add 10x to both sides

∴ The equation of the median is 10x + 6y = 39

* The equation of the median of the trapezoid is 10x + 6y = 39

7 0

3 years ago

Write and solve a system of equations that represents each situation.

kotegsom [21]

(7+x)+x=15
I did trial and error to get x=4.

4 0

3 years ago

Given the system of linear equations:

Vanyuwa [196]

Answer:

Step-by-step explanation:

hello :

Part A : x+6y =6 means : 6y = - x+6

so : y = (-1/6)x+1 an equation for the line (D)

y = (1/3)x -2 is the line (D')

PartB : solution of the system : y = (-1/6)x+1 ....(1) color red

y = (1/3)x -2 ....(2) color bleu

is the intersection point : (6 ; 0)

PartC : Algebraically by (1) and (2) : (-1/6)x+1 = (1/3)x -2

(-1/6)x - (1/3)x = -2-1

(-x-2x)/6= -3

-3x = -18

so : x = 6 put this value in (1) or (2) : y = (-1/6)(6)+1 =0 the solution is : (6 ;0)

3 0

3 years ago