The pentagon is translated 1 unit to the left, so the points move to the left by 1 unit. Moving left or right changes the x value, when you move right, the x value increases, when you move left, x decreases. Since x is going left 1 unit:
So x - 1
10 units down. Moving up down or up changes the y value, when you move down, y decreases, when you move up, y increases. Since the pentagon is going down 10 units:
y - 10
Your answer is A
Answer:
13/12
Step-by-step explanation:
1-2/3+9/12
least common denominator is 12
12/12 - 8/12+9/12
13/12
Sorry man but I have no idea you could try google
x=0
y=-2
You'd put them in an ordered point, so (0,-2).
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
