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I am Lyosha [343]
2 years ago
11

Solve for x: 4x+9/2 1/3=3x/0.5

Mathematics
2 answers:
otez555 [7]2 years ago
6 0

Answer:

Which of the following statements about the First Amendment’s religion clause are true?

Check all of the boxes that apply.Which of the following statements about the First Amendment’s religion clause are true?

Check all of the boxes that apply.Which of the following statements about the First Amendment’s religion clause are true?

Check all of the boxes that apply.

Step-by-step explanation:

Which of the following statements about the First Amendment’s religion clause are true?

Check all of the boxes that apply.Which of the following statements about the First Amendment’s religion clause are true?

Check all of the boxes that apply.Which of the following statements about the First Amendment’s religion clause are true?

Check all of the boxes that apply.Which of the following statements about the First Amendment’s religion clause are true?

Check all of the boxes that apply.

muminat2 years ago
3 0

Answer:

1/3

Step-by-step explanation:

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A line passes through the points (9,6) and (6,5). What is its equation in slope-intercept form?
Tju [1.3M]

Answer:

Y=X/3+3

Step-by-step explanation:

M= Y2-Y1/X2-X1

  = 5-6/6-9

  = -1/-3

  = 1/3

sub x=6, y=5, M=1/3 into Y=MX+C

5=6/3+C

5=2+C

5-2= 2+C-2

3=C

5 0
2 years ago
Suppose that a large mixing tank initially holds 400 gallons of water in which 70 pounds of salt have been dissolved. Pure water
Setler79 [48]

Answer:

Step-by-step explanation:

Given that a large mixing tank initially holds 400 gallons of water in which 70 pounds of salt have been dissolved. Pure water is pumped into the tank at a rate of 4 gal/min, and when the solution is well stirred, it is then pumped out at the same rate.

Let Q(t) be the quantity of salt at time t.

Q(0) = 70 pounds

Inflow of water = outflow = 4 gal/min

So resulting volume of tank at time t = 400 gallons

Rate of change of salt = inflow - outflow

= 0 - \frac{Q(t)}{400}

i.e. \frac{dQ}{dt} =\frac{-Q(t)}{400}

This is a variable separable equation

\frac{dQ}{Q}=-\frac{dt}{400} \\ln Q = {-\frac{t}{400}} +C\\Q = A e^{-\frac{t}{400}}

Use when t =0 Q = 70

A =70

So A(t) = Q(t) = 70 e^{-\frac{t}{400}} and

A(0) = Q(0) = 70 lbs.

7 0
3 years ago
The 24 students in Mr. Brown’s homeroom sold 72 magazine subscriptions. The 28 students in Mrs. Garcia‘s homeroom sold 98 magazi
KATRIN_1 [288]
Mr. brown students sold 3 magazines each while Mrs. Garcia students sold 3.5 magazines each. Mrs. Garcia sold more magazines per student
3 0
3 years ago
Help!!<br> What is the relationship between the corresponding angle bisectors BD and XZ?
Harrizon [31]

Answer:

XZ = 2.5 BD

Step-by-step explanation:

Comparing the two triangles,

\frac{BD}{BC} = \frac{XZ}{XY}

\frac{6}{8} = \frac{XZ}{20}

⇒ XZ = \frac{20*6}{8}

         = 15

XZ = 15

So that,

BD:XZ = 6:15

           = 1:2.5

Therefore, the relationship between BD and XZ is XZ = 2.5 BD.

8 0
3 years ago
HELP ME QUICK<br> Determine a range for the missing side of the triangle below.
ElenaW [278]

Answer:

It is an isosceles triangle.

Angle R = 65 degrees

If side RT = 1 then sides SR and ST = 1.1831

Step-by-step explanation:

6 0
3 years ago
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