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hammer [34]
3 years ago
7

5x² - 4x + 7 - (2x² - 2x - 3) resolver paso a paso xfas

Mathematics
1 answer:
DaniilM [7]3 years ago
5 0
Simplified into 5x^-2x^2 +2x+8
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Which of the following are accurate descriptions of the distribution below?
mart [117]

The single apple on day 10 is an outlier because it is all by its self and the there is a cluster from 4 to 6 because there are multiple apples on days 4, 5, and 6 so your answers would be A and B :)

5 0
3 years ago
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Which graph represents a function?<br> 2<br> 1<br> 23<br> 23<br> 2 3 4 5
Andrej [43]

Answer:

D, the graph in the bottom row, on the right side

Step-by-step explanation:

A function will not have repeating x values, and the graph on the bottom right is the only that passes the vertical line test(meaning there are no repeating x values).

6 0
4 years ago
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A ladder is placed against the side of a house. The top of the ladder is 12 feet above the ground. The base of the ladder is 5 f
Colt1911 [192]
This is the Pythagorean theorem where the 2 legs of a triangle squared add up to equal the squared hypotenuse (a^2 + b^2 = c^2)

The equation would be
12^2 + 5^2 = x^2

144 + 25 = 169

The square root of 169 = 13

Answer - 13 ft
3 0
3 years ago
Just need to know what x is haha
marishachu [46]

Answer: x=14

Step-by-step explanation:

The angles in a triangle are equal to 180 so

6x + 3 + 5x + x + 9 = 180

12x + 12 = 180

      -12     -12

12x = 168

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4 0
4 years ago
What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?
Harman [31]

Answer:

\boxed{ \bold{ \huge{  \boxed{ \sf{ \: 14.25 \: \% \: }}}}}

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

\boxed{ \sf{Amount =  \: Principal + Interest}}

plug the values

⇒\sf{14550 = 6000 + Interest}

Swap the sides of the equation

⇒\sf{6000 + Interest = 14550}

Move 6000 to right hand side and change its sign

⇒\sf{Interest = 14550 - 6000}

Subtract 6000 from 14550

⇒\sf{Interest = \: 8550 \: }

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

{ \boxed{ \sf{Rate =  \frac{Interest \times 100}{Principal \times Time}}}}

plug the values

⇒\sf{ Rate = \frac{8550  \times 100}{6000 \times 10} }

Calculate

⇒\sf{Rate =  \frac{855000}{60000} }

⇒\sf{Rate = 14.25 \: \% \: }

Hope I helped!

Best regards!!

8 0
3 years ago
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