Does this image have a set of inputs to a set of possible outputs where each input is related to exactly one outputs Yes or No?

Mathematics

1 answer:

borishaifa [10]3 years ago

3 0

Answer: Yes

This graph passes the vertical line test. This is a test where we try to draw a single vertical line through more than one point on the curve. In this case, such a thing is not possible. Any input x leads to exactly one output y. This graph is a function.

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Find the vertex, the axis of symmetry, and the y-intercept of the graph.

UNO [17]

Given:

Given that the graph of the parabola.

We need to determine the vertex, the axis of symmetry and the y - intercept of the graph.

Vertex:

The vertex of the parabola is the point at which the parabola changes its direction.

From the graph, it is obvious that the parabola changes its direction at the point (-2,0)

Hence, the vertex of the graph is (-2,0)

Axis of symmetry:

The axis of symmetry is the line that divides the parabola exactly into two equal halves.

Hence, from the graph, it is obvious the line x = -2 divides the graph exactly into two equal halves.

Hence, the axis of symmetry is x = -2.

y - intercept:

The y - intercept of the parabola is the value of y when x = 0.

In other words, the y - intercept of the graph is the value of y when the line passes through the y - axis.

Thus, from the graph it is obvious that when x = 0, the value of y is -3.

Hence, the y - intercept of the graph is -3.

6 0

3 years ago

Suppose that 5 out of 13 people are to be chosen to go on a mission trip. In how many ways can these 5 be chosen if the order in

algol [13]

5 People can be chosen in 1287 ways if the order in which they are chosen is not important.

Step-by-step explanation:

Given:

Total number of students= 13

Number of Students to be selected= 5

To Find :

The number of ways in which the 5 people can be selected=?

Solution:

Let us use the permutation and combination to solve this problem

$nCr=\frac{(n)!}{(n-r)!(r)!}$

So here , n =13 and r=5 ,

So after putting the value of n and r , the equation will be

$13C_5=\frac{(13)!}{(13-5)!(5)!}$

$13C_5=\frac{(13 \times12 \times11 \times10 \times9 \times8\times7 \times6 \times5 \times4 \times3 \times2 \times1)}{(8 \times7 \times6 \times5 \times4 \times3 \times2 \times1)(5 \times4 \times3 \times2 \times1)}$