2x^2 + x + 3=0 has only complex roots.
The determinant is 1-4*2*3 = -23
-23 (or any determinant) is the part under the square root sign, If that determinant is negative, knowing you cannot take the square root of a negative number, we know the answers must be complex.
58 is 5 tens (5*10) and 8 ones (8*1)
Answer:
the last option is the correct one
Step-by-step explanation:
Step-by-step explanation:
1. you set each expression equal to 0.
x-7=0 and x+3=0
2. Next you need to get the variable by itself so you would add 7 to both sides on the first equation and subtract 3 from both sides for the second one.
3. So your answers would be x=7 and x=-3. Those are the zeros.
