Answer:
To find the answers, all I have to do is apply the operations (plus, minus, times, and divide) that they tell me to, in the order that they tell me to.
(f + g)(x) = f (x) + g(x)
= [3x + 2] + [4 – 5x]
= 3x + 2 + 4 – 5x
= 3x – 5x + 2 + 4
= –2x + 6
(f – g)(x) = f (x) – g(x)
= [3x + 2] – [4 – 5x]
= 3x + 2 – 4 + 5x
= 3x + 5x + 2 – 4
= 8x – 2
(f × g)(x) = [f (x)][g(x)]
= (3x + 2)(4 – 5x)
= 12x + 8 – 15x2 – 10x
= –15x2 + 2x + 8
\left(\small{\dfrac{f}{g}}\right)(x) = \small{\dfrac{f(x)}{g(x)}}(
g
f
)(x)=
g(x)
f(x)
= \small{\dfrac{3x+2}{4-5x}}=
4−5x
3x+2
My answer is the neat listing of each of my results, clearly labelled as to which is which.
( f + g ) (x) = –2x + 6
( f – g ) (x) = 8x – 2
( f × g ) (x) = –15x2 + 2x + 8
\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}(
g
f
)(x)=
4−5x
3x+2
Step-by-step explanation:
4/5 recommend, so about 4/5(120) = 96 doctors recommend the brand.
If the length of a rectangle is 3m longer than its width, then:
L=W+3
Is the area really 154^2? Or is it 154m^2? If yes, then:
A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
0=(W-11)(W+14)
This means either (W-11) or (W+14) is equal to zero so:
W=11 and W=-14
To find out let's substitute the numbers:
154=(11+3)(11)
154=154
Therefore, the width of the rectangle is 11m
Equation #1:
|2x - 3| = 17
The first solution is
2x - 3 = 17
2x = 17 + 3 = 20
x = 10
The second solution is
3 - 2x = 17
-2x = 17 - 3 = 14
x = -7
The solutions are x = 10 or x = -7.
Equation #2:
|5x + 3| = 12
The only solution is
5x + 3 = 12
5x = 12 - 3 = 9
x = 9/5
Let us examine the given answers.
a. Equation #1 and #2 have the same number of solutions.
FALSE
b. Equation @1 has more solutions than Equation #2.
TRUE
c. Equation #1 has fewer solutions than equation #2.
FALSE
d. None of the statements a,b, or c apply.
FALSE
Answer: b.
Answer:
i think you r missing some questions r u doing degrees or something else i am not sure
Step-by-step explanation:
