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stira [4]
3 years ago
15

PLEASE HELP IM BEGGING YOU ITS DUE IN 15 MIN ILL GIVE BRAINEST AND PTS

Mathematics
1 answer:
lys-0071 [83]3 years ago
4 0

answer:

you just have to shrink it down to 4cm then to 2cm

i wish i could help out more, but i would need to have access to the form

hopefully, this helps anyhow :)

good luck

have a great day !!

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m_a_m_a [10]

Answer: 178.31

Step-by-step explanation: subtract 574.54 by 396.23

8 0
3 years ago
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Your patience while we update our system.
Masja [62]

Answer:

equation: 320+x=360, answer: 40

Step-by-step explanation:

add 100,200 and 100 to get 320

360-320=40

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8 0
3 years ago
A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?
seraphim [82]

Answer:

P\left(E\right)=\frac{55}{1024}

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

nCr=\frac{n!}{r!\left(n-r\right)!}

Plug in n = 12 and r = 9

       =\frac{12!}{9!\left(12-9\right)!}

       =\frac{12!}{9!\cdot \:3!}

       =\frac{12\cdot \:11\cdot \:10}{3!}            ∵ \frac{12!}{9!}=12\cdot \:11\cdot \:10

       =\frac{1320}{6}                   ∵ 3!\:=\:3\times 2\times 1=6

       =220

Thus, the probability will be:

P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}

         =\frac{220}{4096}

         =\frac{55}{1024}

Thus, the probability of the coin landing tails up exactly nine times will be:

P\left(E\right)=\frac{55}{1024}

4 0
3 years ago
Taylor has a $30 gift card that she can spend at the store. She has already bought
Rudik [331]
That’s 30 dollars she has
5 0
3 years ago
My Notes A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1600 hours and
Evgen [1.6K]

Answer:

The bulbs should be replaced each 1436.9 hours.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1600, \sigma = 70

How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?

This is the first percentile of hours. So it is X when Z has a pvalue of 0.01.

So it is X when Z = -2.33.

Z = \frac{X - \mu}{\sigma}

-2.33 = \frac{X - 1600}{70}

X - 1600 = -2.33*70

X = 1436.9

The bulbs should be replaced each 1436.9 hours.

6 0
3 years ago
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