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2 years ago

Find the value of x. Express your answer in simplest radical form.

Mathematics

1 answer:

Rainbow [258]2 years ago

5 0

Answer:

$\sin(45) = \frac{x}{5} \\ \\ = > \frac{ \sqrt{2} }{2} = \frac{x}{5} \\ \\ < = > x = \frac{5 \sqrt{2} }{2}$

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All of these are considered characteristics of Treasury Bills or T-Bills, except:

dezoksy [38]

Answer:

c. T-Bills are sold in maximum units of $500.

Step-by-step explanation:

T-Bills are sold in maximum units of $500 is not or will not be considered as a characteristic of Treasury Bill.

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2 years ago

Rita has already prepared 3 kilograms of dough and will continue preparing 1 kilogram of dough every hour. How much dough did Ri

Digiron [165]

Answer:

Step-by-step explanation:

9+3=12

hope it helps

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3 years ago

Beth rode her bike for the following distance each day

zhuklara [117]

Monday: 3 1/4 miles
Tuesday: (3 1/4)(2/3) = 2 1/6 miles
Wednesday: (2 1/6)(2) = 4 1/3 miles
Thursday: (4 1/3)(3/4) = 3 1/4 miles

Add them all up: 13 miles

She has not reached her goal, she needs to ride her bike 2 more miles to reach her goal.

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3 years ago

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velikii [3]

I DONT KNOW LOL PLS STOP CHEATING

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2 years ago

The equation t^3=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A

ankoles [38]

Answer:

2√2

Step-by-step explanation:

We can find the relationship of interest by solving the given equation for A, the mean distance.

<h3>Solve for A</h3>

$T^3=A^2\\\\A=\sqrt{T^3}=T\sqrt{T}\qquad\text{take the square root}$

<h3>Substitute values</h3>

The mean distance of planet X is found in terms of its period to be ...

$D_x=T_x\sqrt{T_x}$

The mean distance of planet Y can be found using the given relation ...

$T_y=2T_x\\\\D_y=T_y\sqrt{T_y}=2T_x\sqrt{2T_x}=(2\sqrt{2})T_x\sqrt{T_x}\\\\D_y=2\sqrt{2}\cdot D_x$

The mean distance of planet Y is increased from that of planet X by the factor ...

2√2

8 0

2 years ago