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3 years ago

PLEASE HELP THIS IS A MONTH LATE

Mathematics

1 answer:

Zina [86]3 years ago

6 0

Answer:

1. x =-4 (-4,27)

x =0 (0,3)

x = 2 (2 , -9)

2. x = -1 (-1 , 3)

x = -2 (-2 , 2)

x = -3 ( -3, 1)

3. x = -3 (-3 , 13)

x = 1 (1 , 1)

x = -2 ( -2, 10)

4. x =2 (2 , 24)

x = 3 (3 , 30)

x = -2 (-2 , 0)

5.x = -3 (-3 , -2)

x = 2 (2 ,-12 )

x =4 (4 , -16)

6. x = -1 (-1 , -2)

x = 0 (0 , 2)

x = 2 (2 , 10)

7. x = -2 (-2 , -10)

x = 0 (0 , -14)

x = 3 (3 , -20)

(pls mark brainliest <3 ty)

Step-by-step explanation:

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Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r

ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = $\frac{\sum X}{n}$ = 21.88 ounces

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.201 ounces

n = sample of boxes = 12

$\mu$ = population mean weight

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 90% confidence interval for the population mean, </u> $\mu$ <u> is ;</u>

P(-1.796 < $t_1_1$ < 1.796) = 0.90 {As the critical value of t at 11 degrees of

freedom are -1.796 & 1.796 with P = 5%}

P(-1.796 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.796) = 0.90

P( $-1.796 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

<u>90% confidence interval for</u> $\mu$ = [ $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $21.88-1.796 \times {\frac{0.201}{\sqrt{12} } }$ , $21.88+1.796 \times {\frac{0.201}{\sqrt{12} } }$ ]

= [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

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3 years ago

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Answer:

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Step-by-step explanation:

3(5s + 2)

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3 years ago

Read 2 more answers

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For instance, let's choose another value, say, 8. So substituting:

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