Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer:
Step-by-step explanation:
If it's (-216):
(-216) + 3(5 - 4 x 2)
(-216) + 3( -3)
(-216) -9
-225
If it's -2(16):
-2(16) + 3(5 - 4 x 2)
-2(16) + 3(-3)
-32 - 9
-41
Hello!
Answer:
1. x= 1 / y= 2 / z= -3 / <u>(1 ; 2 ; -3)</u>
2. x= 3 / y= -5 / z= 8 / <u>(3 ; -5 ; 8)</u>
Step-by-step explanation:
55
You Times 20% by 5 to get fully 100%
So if 11 is 20%
You have to Times 11 by 5 to get fully 100%
11 x 5 is 55.
The answer is 55
Answer:
yeah sure
Step-by-step explanation:
because I'm friendly
. To check this we can just look at the side lengths if the triangles. 
has a length of 8 by looking at the graph, and 
has a length of 2 from the graph too. So when we put those lengths
into a fraction, it simplifies to 