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lianna [129]
3 years ago
15

F(x) = 4x + 3 for f(-8).

Mathematics
2 answers:
yarga [219]3 years ago
6 0

Answer:

-29

Step-by-step explanation:

plz brainliestt

Thepotemich [5.8K]3 years ago
6 0

Answer:

-29

Step-by-step explanation:

f(x) = 4x + 3

f(-8) = 4(-8) + 3

f(-8) = -32 + 3

f(-8) = -29

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A hubcap has a radius of 40in. What is the area of the hubcap
stich3 [128]

Answer:

5,024 inches squared

Step-by-step explanation:

Since the area of a circle is pi r^2, we basically have to replace the r with 40, since it's the radius. Therefore when replaced, it would be pi(40)^2. This makes 1600pi. Pi is technically 3.14, so I multiplied 3.14 and 1600 to get 5,024 inches squared.

8 0
3 years ago
I need help please help
monitta

Answer:

with wut XD

Step-by-step explanation:

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3 years ago
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A regular Pentagon with sides 40cm what is the perimeter​
grigory [225]

Perimeter = namely the length of outside bordering,

well, this is a PENTAgon, or PENTA=5 or namely 5 sides, is regular so each side is the same length, so we have a polygon with 5 sides each measuring 40cm, well, its perimeter is just 40+40+40+40+40 = 200.

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3 years ago
A number is chosen at random from 1 to 50. Find the probability of selecting numbers less than 35
Karo-lina-s [1.5K]

Answer:

3?

Step-by-step explanation:

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3 years ago
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a parabola has an x-intercept at 2, its axis of symmetry is the line x=4, and the y-coordinate of its vertex is 6. Determine the
nlexa [21]

Answer:

The standard equation of the parabola is:

y=-\frac{3}{2}x^2+12x-18

Step-by-step explanation:

An x intercept of 2 means that the point (2, 0) is in the graph of the parabola.

We can also write the general expression for the parabola in vertex form, since we can use the information on the coordinates of the vertex: (4, 6) - recall that the axis of symmetry of the parabola goes through the parabola's vertex, so the x-value of the vertex must be x=4.

y-y_{vertex}=a\,(x-x_{vertex})^2\\y-6=a\,(x-4)^2

Now we can find the value of the parameter "a" by using the extra information about the point (2, 0) at which the parabola intercepts the x-axis:

y-6=a\,(x-4)^2\\0-6=a\,(2-4)^2\\-6=a\,4\\a=-\frac{6}{4} =-\frac{3}{2}

Then the equation of the parabola becomes:

y-6=-\frac{3}{2} \,(x-4)^2\\y-6=-\frac{3}{2} (x^2-8x+16)\\y-6=-\frac{3}{2}x^2+12x-24\\y=-\frac{3}{2}x^2+12x-18

7 0
4 years ago
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