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3 years ago

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A company charges $7 for a T-shirt and ships any order for $22. A school principal ordered a number of T-shirts for the school s

tore. The total cost of the order was $1,520. Which equation can be used to find the number of shirts ordered
A.
1,520=x+22(7)
B.
1,520=22x+7
C.
1,520=7x+22x
D.
1,520=7x+22

1 answer:

Harlamova29_29 [7]3 years ago

5 0

Answer: The awnser would be D

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Solve the system of linear equations by ellmination. 5x + 9y = -11 3x + 9y = -3 A. (-4,-1) -B. (-1, –4) C. (-4,1) D. (1,-4)

valentina_108 [34]

Answer:

Step-by-step explanation:

5x + 9y = -11

3x + 9y = -3

5x + 9y = -11

-3x - 9y = 3

2x = -8

x = -4

-12 + 9y = -3

9y = 9

y = 1

(-4, 1)

Answer is C

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3 years ago

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

Ugo [173]

Answer:

$Side\ B = 6.0$

$\alpha = 56.3$

$\theta = 93.7$

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with $\alpha, \beta, \theta$

[See Attachment for Triangle]

$A = 10cm$

$C = 12cm$

$\beta = 30$

What the question is to calculate the third length (Side B) and the other 2 angles ( $\alpha\ and\ \theta$ )

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

$B^2 = A^2 + C^2 - 2ABCos\beta$

Substitute: $A = 10$ , $C =12$ ; $\beta = 30$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30$

$B^2 = 100 + 144 - 240*0.86602540378$

$B^2 = 100 + 144 - 207.846096907$

$B^2 = 36.153903093$

Take Square root of both sides

$\sqrt{B^2} = \sqrt{36.153903093}$

$B = \sqrt{36.153903093}$

$B = 6.0128115797$

$B = 6.0$ <em>(Approximated)</em>

Calculating Angle $\alpha$

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute: $A = 10$ , $C =12$ ; $B = 6$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 180 - 144 *Cos\alpha$

Subtract 180 from both sides

$100 - 180 = 180 - 180 - 144 *Cos\alpha$

$-80 = - 144 *Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}$

$\frac{-80}{-144} = Cos\alpha$

$0.5555556 = Cos\alpha$

Take arccos of both sides

$Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)$

$Cos^{-1}(0.5555556) = \alpha$

$56.25098078 = \alpha$

$\alpha = 56.3$ <em>(Approximated)</em>

Calculating $\theta$

Sum of angles in a triangle = 180

Hence;

$\alpha + \beta + \theta = 180$

$30 + 56.3 + \theta = 180$

$86.3 + \theta = 180$

Make $\theta$ the subject of formula

$\theta = 180 - 86.3$

$\theta = 93.7$

5 0

3 years ago

BRAINLIEST FOR BEST ANSWER

Temka [501]

Answer:

Option C is correct

The coordinate of C' or the transformed point of C is (-6, 5)

Step-by-step explanation:

From the given graph:

In triangle ABC:

Coordinate of C is:

C(-3, 4)

The rule of transformation is given:

$(x, y) \rightarrow (x-3, y+1)$

We have to find the coordinate of C'.

Apply the transformation on coordinate C:

$C(-3, 4) \rightarrow C'(-3-3, 4+1) = C'(-6, 5)$

Therefore, the coordinate of C' is (-6, 5)

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3 years ago

What is the equation of the line that passes through the point (-2,3) and is parallel to the line whose equation is y = 3/2x - 4

Kisachek [45]

Answer:

y = 3/2x + 6

Step-by-step explanation:

y = 3/2x - 4

y-intercept through point (-2, 3):

3 = 3/2(-2) + b

3 = -3 + b

b = 6

Equation of line:

y = mx + b

y = 3/2x + 6

**Parallel line share the same slope, in this case 3/2.

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3 years ago

At 4:00 AM, the temperature is – 12 °F. If the temperature drops 3 °F per hour, what will the temperature be at 6:00 AM?

Scilla [17]

The answer would be -18°F at 6AM
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3 years ago

Read 2 more answers