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pentagon [3]
3 years ago
14

Harrington Corporation produces three products, A, B, and C. Pertinent information on these products is as follows: ProductSelli

ng Price per UnitVariable Cost per UnitFixed Costper UnitDL Hoursper UnitA (Anchor bolts)$4.00 $1.00 $2.00 2 B (Bearings)$3.50 $0.50 $2.00 2 C (Castings)$6.00 $2.00 $3.00 3 There are 150 direct labor hours available. Machine-hour capacity allows 100 anchor bolts, only; 50 bearings, only; 40 casters, only; or any combination of the three that does not exceed the capacity. The direct labor hour constraint for Harrington's linear programming model is: ___________
Business
1 answer:
Over [174]3 years ago
8 0

Answer:

Labour hours constraint :  2a + 2b + 3c ≤ 150

Explanation:

<em>Linear programming is a mathematical model that is used to solve a problem when a firm wants to maximize profit in the midst of multiple resource constraints.</em>

The following steps should be followed:

<em>Step 1: Define the variables</em>

a= the units of product Anchor

b=  the units of product Bearing

c= the units of product Casting

<em>Step 2: Define the constraints:</em>

The constraints represent the limitations which could be resource; in this case machine hours and direct labour hours. Since the constraint in focus is labour hours , so we only consider it.

Subject

Constraints:  Labour hours : 2a + 2b + 3c ≤ 150

Non-negativity constraints a, b , c ≥ 0

Since the total available labour hours is 150 hours then the total consumption hours can either be equal to or less than 150, but can never be higher than 150.

The labour hours constraint  is represented by 2a + 2b + 3c ≤ 150

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1 year ago
The _____ is a strategic management framework that proposes that critical resources and capabilities frequently are embedded in
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4 years ago
The Centers for Disease Control and Prevention (CDC) defines a healthy sleep duration
laiz [17]

a. The point estimate of the married people that sleep well is = 0.6299. The confidence interval for the mean hours of sleep for those that have never been married but report good sleep is 0.6186, 0.6412

b. The point estimate of the number of hours for people that have never been married = 7.2257

95% confidence interval for the mean number of  hours of sleep for those who have never been married = 7.2065, 7.2447

c. the estimated number of sleep for those that have never been married = 7.729 hours

a. The point estimate

P=\frac{Xp}{n}

Xp = successes\\n = sample size\\

Those who have never been married n = 7044

Xp = those who sleep for 7 hours at least

To get Xp, the <u>excel function </u>

Countif(range, criteria)

Countif(A:A, >=7)

This gives Xp = 4437

Point estimate =

\frac{4477}{7044}

= 0.6299

The point estimate of the married people that sleep well is = 0.6299

At 95% interval of confidence,

α = 1-0.95 = 0.05

α/2 = 0.05/2 = 0.025

Z0.025 = 1.96 ( Use the standard probability normal table)

Margin of Error

=M.E = 1.96\sqrt \frac{0.6299(1-0.6299)}{7044} \\\\= 1.96\sqrt{0.000033} \\\\1.96*0.0057

= 0.0113

The 95% confidence interval

= 0.6299 - 0.0113 , 0.6299 + 0.0113

= 0.6186, 0.6412

The confidence interval for the mean hours of sleep for those that have never been married is 0.6186, 0.6412

b. Sample mean

x = ∑x/n

x = number of sleep of the never been married

Mean is calculated using excel function

Average(range)

Average(a:a)

This gives the sample mean = 7.2257

The point estimate of the number of hours for people that have never been married = 7.2257

<u>Standard deviation</u> using excel =

Stdev(A:A) = 0.8211

Margin of error =1.96*\frac{0.8211}{\sqrt{7044} }

= 0.0192

The<u> confidence interval</u> =

= 7.2257-0.0192, 7.2257+0.0192

= 7.2065, 7.2447

95% confidence interval for the mean number of  hours of sleep for those who have never been married = 7.2065, 7.2447

c. From the available data, the mean number of sleep per day that is gotten from the 4437 people that are unmarried and sleep healthily for at least 7 hours = 34295.1

Mean = 34295.1/4437

= 7.729

the estimated number of sleep for those that have never been married = 7.729 hours

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Answer:

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