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3 years ago

Ms/d/e/1FAIpQLSdl9w5bgrlNmTSDiyaGD8reu YA3SDQrcu6iTo-N1FBDnkxOTQ/viewform?hr_submission=chk

Chemistry

1 answer:

IRISSAK [1]3 years ago

5 0

Answer:

Oxygen

Explanation:

This is why we NEED plants, they "eat" Carbon dioxide to give us oxygen during photosynthesis.

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A Silty Clay (CL) sample was extruded from a 6-inch long tube with a diameter of 2.83 inches and weighed 1.71 lbs. (a) Calculate

inna [77]

Answer:

a) the wet density of the CL sample is 0.0453 lb/in³

b) the water content in the sample is 65.37%

c) the dry density of the CL sample is 0.0274 lb/in³

Explanation:

Given that;

diameter d = 2.83 in

length L = 6 in

weight m = 1.71 lbs

A piece of clay sample had wet-weight of 140.9 grams and dry-weight of 85.2 grams

a) wet density of the CL sample

wet density can be expressed as p = M /v

V is volume of sample which is; π/4×d²×L

so p = M / π/4×d²×L

we substitute

p = 1.71 / (π/4 × (2.83)²× 6

p = 1.71 / 37.741

p = 0.0453 lbs/in³

so the wet density of the CL sample is 0.0453 lb/in³

water content of sample is taken as;

w = (wet_weight - dry_weight) / dry_weight

we substitute

w = (140.9 - 85.2) / 85.2

w = 55.7 / 85.2

w = 0.6537 = 65.37%

therefore the water content in the sample is 65.37%

dry density of the CL sample

to determine the dry density, we say;

Sd = p / ( 1 + w )

we substitute

Sd = 0.0453 / ( 1 + 0.6537)

Sd = 0.0453 / 1.6537

Sd = 0.0274 lb/in³

therefore the dry density of the CL sample is 0.0274 lb/in³

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3 years ago

If an element only partially conducts electricity, it would be part of the _______ category. *

dmitriy555 [2]

It would be in the transition metals

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A 410 L volume of nitrogen gas is cooled from 61 C to -25 C. What is the volume of the nitrogen at the lower temperature if all

Lena [83]

Answer:

$304.5\text{L}$

Explanation:

Here, we want to get the volume of the nitrogen gas at the lower temperature

From Charles' law, we know that volume and temperature (in Kelvin) are directly proportion

The mathematical relationship is:

$\frac{V_1}{T_1}\text{ = }\frac{V_2}{T_2}$

Where:

V1 is the initial volume which is 410 L

V2 is the final volume which is unknown

T1 is the initial temperature which we will convert to Kelvin by adding 273.15 K, we have it as 61 + 273.15 = 334.15 K

T2 is the final temperature which we have to convert to Kelvin by adding it to 273.15K : We have that as -25 + 273.15 = 248.15 K

Substituting the values, we have it that:

$\begin{gathered} \frac{410}{334.15}\text{ = }\frac{V_2}{248.15} \\ \\ V_2\text{ = }\frac{248.15\text{ }\times410}{334.15} \\ \\ V_2\text{ = 304.5 L} \end{gathered}$

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What is an atom called if the number of electrons is changed

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Answer:

it is called a substance

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Determine the amount of both hydrogen and oxygen in a 500mL sample of Water.

alina1380 [7]

There would be about 1.67 x 10^25 oxygen atoms and about 3.34 x 10^25 hydrogen atoms.

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