A type of physical that occurs between two electrically charged particles?

1 answer:

7 0

Electromagnetism

Theoretically it is a branch of physics that contains two sources. Either electrically charged particles or the behavior between Neutrons and protons etc.

You might be interested in

Osmium is one of the densest elements known, what is its density if 2.72 g has a volume of 0.121 cm3?

AnnZ [28]

Mass / volume = density
2.72g/0.121mL = 22.5g/mL

1cm3 = 1mL

7 0

2 years ago

Read 2 more answers

Calculate the energy for vacancy formation in silver, given that the equilibrium number of vacancies at 800˚C (1073 K) is 3.6 ×

krek1111 [17]

Answer : The energy for vacancy formation in silver is, $1.762\times 10^{-19}J$

Explanation :

Formula used :

$N_v=N\times e^{(\frac{-E}{K\times T})}$

or,

$N=\frac{N_A\times \rho}{M}$

So,

$N_v=[\frac{N_A\times \rho}{M}]\times e^{(\frac{-E}{K\times T})}$

where,

$N_v$ = equilibrium number of vacancies = $3.6\times 10^{23}m^{-3}=3.6\times 10^{20}L^{-1}$

E = energy = ?

M = atomic weight = 107.9 g/mole

$N_A$ = Avogadro's number = $6.022\times 10^{23}mol^{-1}$

$\rho$ = density = $9.5g/cm^3=9.5g/ml=9500g/L$

T = temperature = $800^oC=273+800=1073K$

K = Boltzmann constant = $1.38\times 10^{-23}J/K$

Now put all the given values in the above formula, we get:

$3.6\times 10^{20}L^{-1}=[\frac{(6.022\times 10^{23}mol^{-1})\times 9500g/L}{107.9g/mol}]\times e^{[\frac{-E}{(1.38\times 10^{-23}J/K)\times 1073K}]}$