<h3>Answer:</h3><h3>ok</h3><h3 /><h3 /><h3>Step By Step Explanation:</h3><h3>Cane sugar processing consists of the following steps: sugar cane is crushed, the juice is heated and filtered, then sent to a series of crystallization steps to create crystals of raw sugar, followed by centrifugation to remove any remaining juice or syrup.</h3>

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how many grams of calcium sulfate are produced from 10 grams of calcium nitrate and how many grams of calcium sulfate are produc

AlekseyPX

Answer: 8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} Ca(NO_3)_2=\frac{10g}{164g/mol}=0.061moles$

$\text{Moles of} Li_2SO_4=\frac{10g}{110g/mol}=0.091moles$

$Ca(NO_3)_2+Li_2SO_4\rightarrow 2LiNO_3+CaSO_4$

According to stoichiometry :

1 mole of $Ca(NO_3)_2$ require = 1 mole of $Li_2SO_4$

Thus 0.061 moles of $Ca(NO_3)_2$ will require= $\frac{1}{1}\times 0.061=0.061moles$ of $Li_2SO_4$

Thus $Ca(NO_3)_2$ is the limiting reagent as it limits the formation of product and $Li_2SO_4$ is the excess reagent.

As 1 mole of $Ca(NO_3)_2$ give = 1 mole of $CaSO_4$

Thus 0.061 moles of $Ca(NO_3)_2$ give = $\frac{1}{1}\times 0.061=0.061moles$ of $CaSO_4$

Mass of $CaSO_4=moles\times {\text {Molar mass}}=0.061moles\times 136g/mol=8.30g$

Thus 8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.

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3 years ago