What is an equation of the line that passes through the points (4,-6) and has a slope of -3
1 answer:
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Hello,
y= x^3-4x²-3x+18=(x-3)²*(x+2)
y'=3x²-8x-3
y''=6x-8
1) Stationary points
Maximun: x=-1/3 ==>y=18,5185....
Minimum: x=3 ===>y=0 (double root)
2) x=4/3: point of inflection. (y''=0 and change sign)
y= x^3-4x²-3x+18=(x-3)²*(x+2)
y'=3x²-8x-3
y''=6x-8
1) Stationary points
Maximun: x=-1/3 ==>y=18,5185....
Minimum: x=3 ===>y=0 (double root)
2) x=4/3: point of inflection. (y''=0 and change sign)