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2 years ago

For brainiest:):):):):):):)

Mathematics

2 answers:

Kay [80]2 years ago

8 0

Answer:

#5 decimal: 0.625 percent 62.5%

#6 decimal: 0.16 percent 16.666%

#7 decimal:3.6667 percent 366.67%

#8 decimal:0.003 percent 0.3%

Step-by-step explanation:

Hopes this helps

lora16 [44]2 years ago

3 0

Answer:

0.625 and 62.5%
0.17 and 17%
3.7 and 367%
0.003 and 0.3%

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Express each evaluation 3! • 2!

Scorpion4ik [409]

Answer:

Step-by-step explanation:

3! = 6

2! = 2

6 * 2 = 12

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3 years ago

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Point T is on line segment \overline{SU} SU . Given ST=2x+6,ST=2x+6, TU=4,TU=4, and SU=4x,SU=4x, determine the numerical length

vazorg [7]

Answer: The numerical length of $\overline{SU}$ is 20 units.

Step-by-step explanation:

Given: Point T is on line segment $\overline{SU}$ .

i.e. $\overline{SU}=\overline{ST}+\overline{TU}$ (i)

Since , it is given that ST=2x+6,TU=4, and SU=4x

Substitute these values in (i), we get

$4x= 2x+6 + 4\\\\\Rightarrow\ 4x-2x=10\\\\\Rightarrow\ 2x=10\\\\\Rightarrow\ x=5$

Now, the numerical length of $\overline{SU}= 4(5)=20\ units$

Hence, the numerical length of $\overline{SU}$ is 20 units.

6 0

3 years ago

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NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions

Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector $\vec{v}$ in some vector space $\mathbb R^n$ we have

$\vec{v} = \langle a,b\rangle$

This is the component form. I don't like that way. It is probably used in high school, but

$\vec{v} = \begin{pmatrix} a\\ b\\ \end{pmatrix}$

is preferable because the inner product on $\mathbb R^n$ is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as $\vec{v} = 2i+2j$

For this question, I think you meant

vectors

$\vec{u_1} = (-8, 12)$

$\vec{u_2} = (13, 15)$

Once

$\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}$

Considering that the dot product is

$\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76$

and the norm of $\vec{u_1}$ is $||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}$

and the norm of $\vec{u_2}$ is $||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}$

Thus,

$\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}$

$\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)$

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2 years ago

Can you answer this math homework? Please!

luda_lava [24]

Answer: (3.5,-2)

Step-by-step explanation:

To solve this problem, all we have to do is plug in y=-2 into either equations from step one to find the coordinate. To make sure we have the right x-coordinate, let's plug in y for both equations.

4x-7y=28 [plug in y=-2]

4x-7(-2)=28 [multiply]

4x+14=28 [subtract both sides by 14]

4x=14 [divide both sides by 4]

x=3.5

------------------------------------------------------------------------------------------------------------

6x-5y=31 [plug in y=-2]

6x-5(-2)=31 [multiply]

6x+10=31 [subtract both sides by 10]

6x=21 [divide both sides by 6]

x=3.5

Now, we know the solution to the system is (3.5,-2).

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2 years ago

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The inner square has sides of 3 inches and the outer square has sides

EastWind [94]

X is the hypotenuse of an isosceles triangle. The length of the sides are the difference of the inner and outer squares divided by 2. Which means that the sides of the triangle is 1.5 inches. Using that information, the length of X can be deduced to be 2.12 inches using Pythagoras theorem

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