9514 1404 393
Answer:
(a) not proportional
(b) k = 7/8
Step-by-step explanation:
When a linear equation is of the form ...
y = mx + b
with b ≠ 0, the relation is NOT PROPORTIONAL.
__
If b=0, so the equation is of the form ...
y = kx
then the relation IS PROPORTIONAL. The constant of proportionality is k.
__
(a) Not proportional
(b) Proportional with k = 7/8
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Answer:
; minimum
Step-by-step explanation:
Given:
The function is, 
The given function represent a parabola and can be expressed in vertex form as:
The vertex form of a parabola is 
, where, 
is the vertex.
So, the vertex is .
In order to graph the given parabola, we find some points on it.
Let 
So, the points are 
.
Mark these points on the graph and join them using a smooth curve.
The graph is shown below.
From the graph, we conclude that at the vertex , it is minimum.
Check the picture below.
well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.
bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.
![\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}](https://tex.z-dn.net/?f=%5Cbf%20A%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B4%7D%29%5Cqquad%20B%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B1%7D%29%20~%5Chfill%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B1%7D-%5Cstackrel%7By1%7D%7B4%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B5%7D-%5Cunderset%7Bx_1%7D%7B1%7D%7D%7D%5Cimplies%20%5Ccfrac%7B-3%7D%7B4%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bslope%20of%20AB%7D%7D%7B-%5Ccfrac%7B3%7D%7B4%7D%7D%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Ctextit%7B%5Cunderline%7Bnegative%20reciprocal%7D%20and%20slope%20of%20the%20diameter%7D%7D%7B%5Ccfrac%7B4%7D%7B3%7D%7D)
so, it passes through the midpoint of AB,
so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)
Answer:
∅ ≈ 56.31°
Step-by-step explanation:
The bird is spotted flying 6000 ft from a tower . The distance of the tower from the bird is 6000 ft. The height of the tower is 9000 ft because the observer spot the distance from the top of the tower at a distance of 9000 ft.
The illustration forms a right angle triangle. The adjacent side of the triangle is 6000 ft and the height or opposite side of the triangle is 9000 ft. Using tangential ratio the angle of depression from the bird to the observer can be found as follows.
Let
∅ = angle of depression
tan ∅ = opposite/adjacent
tan ∅ = 9000/6000
tan ∅ = 1.5
∅ = tan⁻¹ 1.5
∅ = 56.309932474
∅ ≈ 56.31°
