1 year ago

Between which two consecutive integers does the cube root of 23 lie

Mathematics

2 answers:

balandron [24]1 year ago

6 0

Answer:

2 and 3

Step-by-step explanation:

consider perfect cubes either side of 23

8 < 23 < 27 , then

$\sqrt[3]{8}$ < $\sqrt[3]{23}$ < $\sqrt[3]{27}$ , that is

2 < $\sqrt[3]{23}$ < 3

diamong [38]1 year ago

5 0

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

F(x)=<img src="https://tex.z-dn.net/?f=%28x%2B1-%7Cx-1%7C%29%2F2" id="TexFormula1" title="(x+1-|x-1|)/2" alt="(x+1-|x-1|)/2" ali

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Answer:

$f(g(x))=\dfrac{|x|+1-||x|-1|}{2}$

Step-by-step explanation:

The most straightforward way is direct substitution of g(x) for x in f(x):

$f(g(x))=\dfrac{|x|+1-||x|-1|}{2}$

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