Question

A bouncy ball is thrown into the air. The height of the bouncy ball above ground can be represented by the function h(t)= −16t^2+46t+6, where h is the height (in feet) of the ball above the ground, and t is the time (in seconds) that has passed since the ball was thrown. How many seconds will it take the ball to reach the ground

Answer 1

t=3 seconds

Step-by-step explanation:

h(t)=0 gives

$-16t^2+46t+6=0\\\\8t^2-23t-3=0\\8t^2-24t+t-3=0\\8t(t-3)+1(t-3)=0\\(t-3)(8t+1)=0\\t=3,-\frac{1}{8} (rejected)$

Answer 2

I don’t understand the question