What is the slope of the line that passes through the points (2, –3) and (–2, 5)? 2 1/2 -1/2 -2
1 answer:
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To evaluate a function at a given input, you have to substitute every occurrence of the variable with that particular value.
So, for the first function, you have
The name of the variable is obviously irrelelvant, so the same goes for the second function:
Answer:
Choice D is correct
Step-by-step explanation:
The first step is to write the polar equation of the conic section in standard form by dividing both the numerator and the denominator by 2;
The eccentricity of this conic section is thus 1, the coefficient of cos θ. Thus, this conic section is a parabola since its eccentricity is 1.
The value of the directrix is determined as;
d = k/e = 3/1 = 3
The denominator of the polar equation of this conic section contains (-cos θ) which implies that this parabola opens towards the right and thus the equation of its directrix is;
x = -3
Thus, the polar equation represents a parabola that opens towards the right with a directrix located at x = -3. Choice D fits this criteria
