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antiseptic1488 [7]
3 years ago
15

How to find the derivative of an integral with bounds.

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
3 0

Answer:

The statement of the fundamental theorem of calculus shows the upper limit of the integral as exactly the variable of differentiation. Using the chain rule in combination with the fundamental theorem of calculus we may find derivatives of integrals for which one or the other limit of integration is a function of the variable of differentiation.

Step-by-step explanation:

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According tp the fundamental theorem of algebra, how many zeros does the polynomial below have? f(x)=x^3-10x^2+27x-12
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The answer is 3.

The fundamental theorem of algebra says that a number of zeros of a polynomial are equal to the highest exponent on a variable. 

The polynomial is <span>f(x)=x</span>³<span>-10x</span>²<span>+27x-12
The highest exponent of a variable x is 3: x</span>³
Therefore, the number of zeroes of the polynomial is 3.
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In which area of the diagram does the number −11 belong?
vesna_86 [32]
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What is the solution to the equation? 5-3x = x - 7 1 O A. 2 OB. 1 OC. C. 2 D. 3​
strojnjashka [21]

Answer:

D. x=3

Step-by-step explanation:

6 0
3 years ago
Given the functions k(x) = 2x2 − 7 and p(x) = x − 4, find (k ∘ p)(x). (k ∘ p)(x) = 2x2 − 8x + 16 (k ∘ p)(x) = 2x2 − 16x + 32 (k
Anuta_ua [19.1K]

Answer:

<h2>(k ∘ p)(x) = 2x² - 16x + 25</h2>

Step-by-step explanation:

k(x) = 2x² - 7

p(x) = x - 4

To find (k ∘ p)(x) substitute p(x) into k(x),

that's replace any x in k(x) by p(x)

We have

(k ∘ p)(x) = 2(x - 4)² - 7

Expand

(k ∘ p)(x) = 2( x² - 8x + 16) - 7

= 2x² - 16x + 32 - 7

Simplify

We have the final answer as

<h3>(k ∘ p)(x) = 2x² - 16x + 25</h3>

Hope this helps you

3 0
3 years ago
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