Question

Pyramid A is 8 in. wide, 8 in. long, and 4 in. tall. Pyramid B has measurements that are twice those of pyramid A. What is the volume of pyramid B divided by the volume of pyramid A?

Answer 1

The answer is 8 inches cubed

Answer 2

   
$\displaystyle \\ V_A = \frac{8\times 8 \times 4}{3} \\ \\ V_B = \frac{16\times 16 \times 8}{3} \\ \\ \frac{V_B}{V_A} = \frac{ \frac{16\times 16 \times 8}{3} }{\frac{8\times 8 \times 4}{3}} = \frac{16\times 16 \times 8}{8\times 8 \times 4} =2\times 2 \times 2 = 2^3 = \boxed{8}$