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Ksivusya [100]
2 years ago
10

Pls help asap!! Hhuwdqnjwl

Mathematics
2 answers:
vampirchik [111]2 years ago
7 0

Answer:

14

Step-by-step explanation:

To get the answer, add the whole numbers together and then add the fractions together:

9 + 4 = 13

(You can even stop here because 14 is the closest to 13)

Now, add the fractions:

\frac{2}{3}+\frac{1}{5}

To add fractions you have to have a common denominator. To find the common denominator multiply 3 by 5, and 5 by 3. Like this:

(\frac{5}{5})\frac{2}{3}  + \frac{1}{5} (\frac{3}{3} )

Simplify:

\frac{10}{15} +\frac{3}{15}              Distribute everything from above

\frac{13}{15}                      Add

So, the whole fraction will look like this 13\frac{13}{15}. This is closest to 14.

Hope this helps!! Ask questions if you need!

vlada-n [284]2 years ago
5 0

Answer:

its b.14

Step-by-step explanation:

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Tom [10]
The answer is 80 because 8>0 80 is a multiple of 5, it’s even and it a two digit number
8 0
3 years ago
Solve for h(2) h(t) = t2 − t + 7
zubka84 [21]

if h(t) = t² - t +7

h(2) = -5

I hope it helps

4 0
3 years ago
A robin can fly 10 miles per hour faster than a blue jay. It takes a robin 1 1/2 hours to fly 45 miles.
cricket20 [7]

Answer: 2\dfrac14\text{ hours}

Step-by-step explanation:

Given:  It takes a robin 1\dfrac12 hours to fly 45 miles.

1\dfrac12=\dfrac32

Speed of robin= \dfrac{distance}{time}=\dfrac{45}{\dfrac32}

\dfrac{45}{3}\times2= 15\times2= 30\text{ miles per hour}

A robin can fly 10 miles per hour faster than a blue jay. It

Speed of Blue jay = Speed of robin - 10 miles per hour

= 30 miles per hour - 10 miles per hour

= 20 miles per hour

Time taken to cover 45 miles = \dfrac{45}{20}=\dfrac{9}{4}=2\dfrac14\text{ hours}

Hence, it will take 2\dfrac14\text{ hours}  by a blue jay to fly that same distance.

4 0
3 years ago
Write the expressions for when you translate the graph of y = x+2 a) one unit up, b) one unit down, c) one unit to the left, d)
Aleksandr-060686 [28]

Answers and Step-by-step explanations:

Vertical transformations affect the entire function, while horizontal transformations influence only the x - only the x is altered. Vertical transformations include vertical stretches and shrinks, reflections over the x axis, and translations up and/or down. Horizontal transformations are horizontal stretches and shrinks, reflections over the y axis, and translations left and/or right.

a) "translate one unit up"; since we're translating <em>up</em>, we know this is a vertical translation, which will affect the entire function. So, the function will go from y = x + 2 to y = (x + 2) + 1 or y = x + 3.

b) "translate one unit down"; again, since we're translating <em>down</em>, we know this is another vertical translation, which will affect the entire function. So, our function goes from y = x + 2 to y = (x + 2) - 1 or y = x + 1.

c) "translate one unit to the left"; since we're translating to the <em>left</em>, we know that this will be a horizontal transformation, which will only affect the x. So our function goes from y = x + 2 to y = (x + 1) + 2 or y = x + 3. (Note that "left" will use a "+" sign because horizontal transformations are weird and "backward")

d) "translate one unit to the right"; again, since we're moving to the <em>right</em>, we know this is another horizontal transformation, which will only affect the x. So our function goes from y = x + 2 to y = (x - 1) + 2 or y = x + 1. (Again note that "right" uses "-" instead of "+" as we would think because horizontal transformations are weirdly "backward").

Hope this helps!

6 0
3 years ago
Read 2 more answers
Does anyone know how to solve this?
MrRissso [65]

9514 1404 393

Answer:

Step-by-step explanation:

The tangent of the angle can be found using the identity for the tangent of the difference of angles.

  tan(α-β) = (tan(α) -tan(β))/(1 +tan(α)tan(β))

The tangent of the angle of each vector is the ratio of the j coefficient to the i coefficient.

  tan(α) = -2/3

  tan(β) = 4/7

  tan(α-β) = (-2/3 -4/7)/(1 +(-2/3)(4/7))

  = (-14-12)/(21 -8) = -26/13 = -2

Then the magnitude of the angle between the vectors is ...

  arctan(2) ≈ 63.43°

5 0
3 years ago
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