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3 years ago

Solve the absolute value equation.

Mathematics

2 answers:

Katarina [22]3 years ago

7 0

Answer:

Step-by-step explanation:

zloy xaker [14]3 years ago

7 0

Answer:

Step-by-step explanation:

Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.

The Absolute Value term is |4x+3|

For the Negative case we'll use -(4x+3)

For the Positive case we'll use (4x+3)

-(4x+3) = 3

Multiply

-4x-3 = 3

Rearrange and Add up

-4x = 6

Divide both sides by 4

-x = (3/2)

Multiply both sides by (-1)

x = -(3/2)

Which is the solution for the Negative Case

(4x+3) = 3

Rearrange and Add up

4x = 0

Divide both sides by 4

x = 0

Which is the solution for the Positive Case

x=-3/2

x=0

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geniusboy [140]

Answer:

Inverse.

Step-by-step explanation:

8 0

4 years ago

write an equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

dimaraw [331]

The equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is $y - 3 = \frac{-7x}{2}+ \frac{21}{4}$

<h3>Solution:</h3>

Given that we have to write equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

Let us first find the slope of given line AB

The slope "m" of the line is given as:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Here the given points are A(-2,2) and B(5,4)

$\text {Here } x_{1}=-2 ; y_{1}=2 ; x_{2}=5 ; y_{2}=4$

$m=\frac{4-2}{5-(-2)}=\frac{2}{7}$

Thus the slope of line with given points is $\frac{2}{7}$

We know that product of slopes of given line and slope of line perpendicular to given line is always -1

$\begin{array}{l}{\text {slope of given line } \times \text { slope of perpendicular bisector }=-1} \\\\ {\frac{2}{7} \times \text { slope of perpendicular bisector }=-1} \\ \\{\text {slope of perpendicular bisector }=\frac{-7}{2}}\end{array}$