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Vadim26 [7]
2 years ago
10

Solve the absolute value equation.

Mathematics
2 answers:
Katarina [22]2 years ago
7 0

Answer:

A

Step-by-step explanation:

zloy xaker [14]2 years ago
7 0

Answer:

A

Step-by-step explanation:

Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.

The Absolute Value term is |4x+3|

For the Negative case we'll use -(4x+3)

For the Positive case we'll use (4x+3)

-(4x+3) = 3

    Multiply

     -4x-3 = 3

    Rearrange and Add up

     -4x = 6

    Divide both sides by 4

     -x = (3/2)

    Multiply both sides by (-1)

     x = -(3/2)

    Which is the solution for the Negative Case

(4x+3) = 3

    Rearrange and Add up

     4x = 0

    Divide both sides by 4

     x = 0

    Which is the solution for the Positive Case

x=-3/2

x=0

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Let AA and BB be events such that P(A∩B)=1/73P(A∩B)=1/73, P(A~)=68/73P(A~)=68/73, P(B)=21/73P(B)=21/73. What is the probability
krok68 [10]

Answer:

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Step-by-step explanation:

Let A and B events. We have defined the probabilities for some events:

P(A') =\frac{68}{73} , P(B) =\frac{21}{73} , P(A \cap B) =\frac{1}{73}

Where A' represent the complement for the event A

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: P(A)+P(A') =1

So for this case we can solve for P(A) like this:

P(A) = 1-P(A') = 1-\frac{68}{73}=\frac{5}{73}

And now we can find P(A \cup B) using the total probability rul given by:

P(A \cup B) = P(A)+P(B) -P(A \cap B)

And if we replace the values given we got:

P(A \cup B) = \frac{5}{73} +\frac{21}{73} -\frac{1}{73}=\frac{25}{73}

And that would be the final answer.

5 0
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