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irga5000 [103]
3 years ago
14

Consider the number 1234. One of your students says that there are 3 tens in 1234. Another one of your students says that there

are 123 tens in 1234. Which student, if any, is correct?
Mathematics
1 answer:
stepladder [879]3 years ago
3 0

Answer:

asdfgv

Step-by-step explanation:

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A packages of 4 socks cost 27.56 what is the unit rate
Brrunno [24]

$27.56/4 =6.89 per sock

3 0
3 years ago
Read 2 more answers
What is the solution of the system? Use substitution. x - y = -6 6x - 3y = -9
elena-14-01-66 [18.8K]

Answer:1.5,-1.5

Step-by-step explanation:

I just answered it

3 0
3 years ago
Please help! Please explain how to do this, I am so lost.
alexdok [17]
Ok, so we know that RST is equal to 6x+12
And RST is also equal to 78 + 3x-12
so we set them equal to each other

6x + 12 = 3x - 12 + 78
And simplify
3x = 54
x = 18

Finally, we solve for the angle with 18 for x

6(18) + 12
108 + 12
120

Hope this helps
8 0
3 years ago
What are the solutions to the system of equations? y=2x^2−6x+3 y=2x+3
adoni [48]

Answer:

Step-by-step explanation:

y=2x²-6x+3

y=2x+3

2x²-6x+3=2x+3

2x²-6x+3-2x-3=0

2x²-8x=0

2x(x-4)=0

x=0,4

y=0+3=3

and y=2(4)+3=11

so solutions are (0,3) and (4,11)

5 0
2 years ago
I have 10 goats, n of which are male. I need to choose 2 of them to make a casserole.
snow_tiger [21]

Answer: There are 4 male goats.

Step-by-step explanation:

We know that n of the 10 goats are male.

The probability that in a random selection, the selected goat is a male, is equal to the quotient between the number of male goats (n) and the total number of goats (10)

The probability is;

p = n/10

Now the total number of goats is 9, and the number of male goats is n -1

then the probability of selecting a male goat again is:

q = (n-1)/9

The joint probability (the probability that the two selected goats are male) is equal to the product of the individual probabilities, this is

P = p*q = (n/10)*((n-1)/9)

And we know that this probability is equal to 2/15

Then we have:

(n/10)*((n-1)/9) = 2/15

(n*(n-1))/90 = 2/15

n*(n-1) = 90*2/15 = 12

n^2 - n = 12

n^2 - n - 12  = 0

This is a quadratic equation, we can find the solutions if we use Bhaskara's formula:

For an equation:

a*x^2  + b*x + c =  0

The two solutions are given by:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

For our case, the solutions will be:

n = \frac{1 +- \sqrt{(-1)^2 - 4*1*(-12)} }{2*1 } = \frac{1+- 7}{2}

The two solutions are:

n = (1 - 7)/2 = -3    (this solution does not make sense, we can not have a negative number of goats)

The other solution is:

n = (1 + 7)/2 = 4

This solution does make sense, this means that we have 4 male goats.

5 0
3 years ago
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