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uysha [10]
3 years ago
6

Haydin chooses a jersey at random and then replaces it. He then selects a second jersey at random. What is the probability that

Haydin selects a striped jersey both times?
Mathematics
2 answers:
nataly862011 [7]3 years ago
4 0

Answer:

1/25

Step-by-step explanation:

4 as fraction 1/25 which is the probability

Elena L [17]3 years ago
3 0

<em>Question:</em>

<em>Haydin chooses a jersey at random and then replaces it. He then selects a second jersey at random. What is the probability that Haydin selects a striped jersey both times. 2 are striped,5 are colored and 3 are white.</em>

Answer:

Probability = 0.04

Step-by-step explanation:

Given

Striped = 2

Colored = 5

White = 3

Required

Determine the probability that both selections are stripped

This is calculated as:

Probability = P(Stripped) * P(Stripped)

Probability = \frac{n(Stripped)}{Total} * \frac{n(Stripped)}{Total}

Probability = \frac{2}{2 + 5 + 3}* \frac{2}{2 + 5 + 3}

Probability = \frac{2}{10}* \frac{2}{10}

Probability = \frac{4}{100}

Probability = 0.04

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Ellen must take 4 courses this semester. She has a list of 3 math courses and 4 science courses to from which to choose. (a) Ini
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Answer:

So the number of total combinations is 35.

Step-by-step explanation:

We know that Ellen must take 4 courses this semester. She has a list of 3 math courses and 4 science courses.  

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7 0
4 years ago
Can someone do 463 ÷ 60 by the standard algorithm
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7 remainder 42

Step-by-step explanation:

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3 years ago
7. In name the bisected angles 1 and 2. If is 4x  3y, can be determined in terms of x and y? If so, state in terms of x+ y expr
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Answer:since there is no diagram i will answer to the best of my ability.

Step-by-step explanation:

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8 0
3 years ago
If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2
Oksanka [162]

If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width

Solution:

Let the length of rectangle=x

Width of rectangle=x/10

Perimeter is 2(Length+Width)

= 2(x+x/10)

Area of Rectangle= Length* Width=x*x/10

As, Perimeter=2(Area)

So,2(x+x/10)=2(x*x/10)

Multiplying the equation with 10, we get,

2(10x+x)=2x²

Adding Like terms, 10x+x=11x

2(11x)=2x^2

22x=2x²

2x²-22x=0

2x(x-11)=0

By Zero Product property, either x=0

or, x-11=0

or, x=11

So, Width=x/10=11/10=1.1

Checking:

So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2

Area=Length*Width=11*1.1=12.1

Hence, Perimeter= 2 Area

As,24.2=2*12.1=24.2

So, Perimeter=2 Area

So, Answer:Length of Rectangle=11 units

Width of Rectangle=1.1 units

7 0
3 years ago
Read 2 more answers
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